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velikii [3]
3 years ago
13

Negative 1 3/5 divided by negative 2/3

Mathematics
2 answers:
Serjik [45]3 years ago
6 0
The answer is 24/10
-1 3/5 = -8/5
-2/3=-3/2
-8/5 times -3/2 = 24/10
When we divide fractions we have to flip the second fraction , then we multiply the fractions , the answer is not negative because a negative times a negative equals to a positive.
Alchen [17]3 years ago
4 0
Im pretty sure its 2.5 if you mean (-1 3/5)/(-2/3)
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Please hurry simplify the expression (15^1/5)^5
Lelu [443]

Answer:

15

Step-by-step explanation:

using the rule of exponents

(a^m)^{n} = a^{mn}

(15^{\frac{1}{5)} } ^{5} = 15^{(1/5(5))} = 15^{1} = 15


5 0
2 years ago
What is the sum of the series? Write in expanded form making sure to show all steps used to find the sum.
san4es73 [151]

Answer:

-16

Step-by-step explanation:

k = 3

-2(3) + 5 = -1

k = 4

-2(4) + 5 = -3

k = 5

-2(5) + 5 = -5

k = 6

-2(6) + 5 = -7

(-1) + (-3) + (-5) + (-7)

= -16

6 0
3 years ago
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A statue of Abraham Lincoln casts a 9-foot shadow at the same time the White House casts a 48-foot shadow. If the White House is
jeka94

Answer: The statue, originally intended to be only 10 feet tall, was on further consideration enlarged so that it finally stood 19 feet tall from head to foot, the scale being such that if Lincoln were standing he would be 28 feet tall.

Step-by-step explanation: hope this helps

8 0
2 years ago
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The lengths of the diagonals of a rhombus are 18 cm and 24 cm. What is its perimeter and what is the distance between the parall
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Try this option:
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3 years ago
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Batteries produced by a manufacturing company have had a life expectancy of 135 hours. Because of an improved production process
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Answer:  c. z = 1.35; Reject the null hypothesis

Step-by-step explanation:

Let \mu be the average life expectancy of its batteries.

As per given , we have

Null hypothesis : H_0 : \mu =135

Alternative hypothesis : H_a : \mu >135

Since H_a is right-tailed and population standard deviation is also known, so we perform right-tailed z-test.

Test statistic : \dfrac{\overlien{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

where, n= sample size

\overlien{x}= sample mean

\mu= Population mean

\sigma=population standard deviation

For n=42,\ \overline{x}=140\ \&\ \sigma=24, we have

z=\dfrac{140-135}{\dfrac{24}{\sqrt{42}}}=1.35015431217\approx1.35

Critical one-tailed test value for 0.10 significance level :

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[When critical value is less than the test statistic value , we reject the null hypothesis .]

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