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Arte-miy333 [17]
2 years ago
10

Find the perimeter of the parallelogram shown. PLEASE HELP

Mathematics
1 answer:
Andreyy892 years ago
5 0

Answer:

46

Step-by-step explanation:

for perimeter just add up the side

9+14+9+14  or  9+14 = 23  then 23* 2 =46

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At what point does the curve have maximum curvature? Y = 4ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as
MAXImum [283]

<u>Answer-</u>

At x= \frac{1}{2304e^4-16e^2} the curve has maximum curvature.

<u>Solution-</u>

The formula for curvature =

K(x)=\frac{{y}''}{(1+({y}')^2)^{\frac{3}{2}}}

Here,

y=4e^{x}

Then,

{y}' = 4e^{x} \ and \ {y}''=4e^{x}

Putting the values,

K(x)=\frac{{4e^{x}}}{(1+(4e^{x})^2)^{\frac{3}{2}}} = \frac{{4e^{x}}}{(1+16e^{2x})^{\frac{3}{2}}}

Now, in order to get the max curvature value, we have to calculate the first derivative of this function and then to get where its value is max, we have to equate it to 0.

 {k}'(x) = \frac{(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})}{(1+16e^{2x} )^{2}}

Now, equating this to 0

(1+16e^{2x})^{\frac{3}{2} } (4e^{x})-(4e^{x})(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x}) =0

\Rightarrow (1+16e^{2x})^{\frac{3}{2}}-(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})

\Rightarrow (1+16e^{2x})^{\frac{3}{2}}=(\frac{3}{2}(1+e^{2x})^{\frac{1}{2}})(32e^{2x})

\Rightarrow (1+16e^{2x})^{\frac{1}{2}}=48e^{2x}

\Rightarrow (1+16e^{2x})}=48^2e^{2x}=2304e^{2x}

\Rightarrow 2304e^{2x}-16e^{2x}-1=0

Solving this eq,

we get x= \frac{1}{2304e^4-16e^2}

∴ At  x= \frac{1}{2304e^4-16e^2} the curvature is maximum.




6 0
3 years ago
Anton will be constructing a segment bisector with a compass and straightedge, while Maxim will be constructing an angle bisecto
elena-14-01-66 [18.8K]

A bisector is a line that divides either a line or an angle into <em>two</em><em> proportionate</em> parts or angles. Thus, Anton's <em>bisector</em> would divide the segment into two <u>equal parts</u>, while Maxim's <em>bisector</em> would divide the angle into two <u>equal angles</u>.

The <u>similarities</u> between their construction are:

  • <em>Intersecting</em> arcs through which the bisector would pass are required.
  • The arcs are dawn using <em>the same</em> radius of any measure.
  • The <em>edges</em> of the arc of the given angle, and the ends of the segment are used as <em>centers</em>.

The <u>differences</u> between their construction are:

  • Anton has to draw two intersecting arcs <u>above</u> and <u>below</u> the segment. While Maxim would draw two intersecting arcs <u>within</u> the lines forming the angles.
  • Anton's bisector would be <em>perpendicular</em> to the segment, while Maxim's bisector would be at <em>an angle</em> which is half of the initial angle.

Visit: brainly.com/question/17247176

3 0
2 years ago
Andrea's living room floor is a rectangle 12 feet by 15 feet. She wants to buy a rug that is geometrically similar to her living
Sliva [168]

Answer:

180 square feet

Step-by-step explanation:

A rug that is geometrically similar to her room floor is one that has the same size as her room floor.

The floor has dimensions 12 feet by 15 feet.

The area of the floor and hence, the rug is:

A = 12 * 15 = 180 square feet

She should buy a rug that is 180 square feet

7 0
3 years ago
Please help u don't get it #begging
Jobisdone [24]
33.C
34.C
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4 0
3 years ago
Multiply the equation 2x+2y=8 by 3. Does the equation have the same solution set?
stepan [7]

Multiply the equation:

2x+2y=8 \mapsto 6x+6y=24

The solution set is the same, because multiplying both sides of an equation by a non-zero number doesn't change the solution set. In fact, if you rewrite the equation as

2x+2y-8=0

Multiplying this by 3 (or whatever number, for all it matters) gives

3(2x+2y-8)=0

Now, a product is zero if and only if at least one of the factor is zero. So, either 3=0 or 2x+2y-8=0

Since the first is clearly impossible, the second one must be true, which is the original equation.

3 0
3 years ago
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