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3 years ago

Combine the like terms and create an equivalent expression: -5r+8r+5

Mathematics

1 answer:

mart [117]3 years ago

7 0

Answer:

3r+5

Step-by-step explanation:

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Suppose that f(5) = 1, f '(5) = 4, g(5) = −9, and g'(5) = 5. Find the following values.

stiv31 [10]

$\bf \begin{cases}
f(5)=1\qquad &f'(5)=4
\\\\
g(5)=-9\qquad &g'(x)=5
\end{cases}
\\\\

\begin{cases}
(f\cdot g)'(5)\impliedby \textit{product rule}
\\\\
\left( \frac{f}{g} \right)'(5)\impliedby \textit{quotient rule}
\end{cases}\\\\
-----------------------------\\\\
(f\cdot g)'(5)\implies f(x)\cdot g(x)\implies 
\begin{array}{llll}
f'(x)g(x)+f(x)g'(x)\\\\
x=5\\\\\
[4\cdot -9]+[1\cdot 5]
\end{array}
\\\\
-----------------------------\\\\
$

$\bf \left( \frac{f}{g} \right)'(5)\implies 
\begin{array}{llll}
\cfrac{f'(x)g(x)-f(x)g'(x)}{[g(x)]^2}\\\\
x=5\\\\
\cfrac{[4\cdot -9]-[1\cdot 5]}{(-9)^2}
\end{array}$

5 0

3 years ago

the track team is trying to reduce their time for a relay race. First they reduce their time by 2.1 minutes. then they are able

koban [17]

Their beginning time was 16.06 minutes.

<u>Step-by-step explanation:</u>

The track team is trying to reduce their time for a relay race.

First they reduce their time by 2.1 minutes, take it as $t_{1}$ . Then they are able to reduce that time by 10 minutes, take it as $t_{2}$ . Let ‘X’ be the time in minutes at the beginning.

Given that their final time is 3.96 minutes, then their beginning time can be calculated as below,

$X-t_{1}-t_{2}=3.96 \text { minutes }$

$X=3.96+t_{1}+t_{2}$

By substituting the values, we get

$X=3.96+2.1+10=16.06 \text { minutes }$

Hence, their beginning time was 16.06 minutes.

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4 years ago