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vlada-n [284]
2 years ago
8

Combine the like terms and create an equivalent expression: -5r+8r+5

Mathematics
1 answer:
mart [117]2 years ago
7 0

Answer:

3r+5

Step-by-step explanation:

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How do you do this and what is the answer
Talja [164]
We know opposite angles in the parallelogram is congruent:

let x to be the unknown angle:

 360=2(110)+2x

360=220+2x

140=2x

x=70

ECF is also 110 because of parallel lines and corresponding angles:




110+x+y=180

110+30+y=180

y=40

so DAE is 40





6 0
2 years ago
ABC and DEF are similar. Find the missing side length.
mrs_skeptik [129]

Answer:

The missing side length is 5

Step-by-step explanation:

Basically 32 to 4 and 56 to 7 is 8 to 1, so you divide 40 by 8 to get the answer, 5

3 0
2 years ago
What is the quotient of
S_A_V [24]
The quotient is (x-2).
6 0
3 years ago
Read 2 more answers
Solve for x.
Ivahew [28]
ANSWER

x=\frac{2-\sqrt{10}} {3}

or

x=\frac{\sqrt{10}+2} {3}

We have

3x^2-4x-2=0

Since we cannot factor easily, we complete the square.

Adding 2 to both sides give,

3x^2-4x=2

Dividing through by 3 gives

x^2-\frac{4}{3}x= \frac{2}{3}

Adding (-\frac{2}{3})^2 to both sides gives

x^2-\frac{4}{3}x+(-\frac{2}{3})^2= \frac{2}{3}+(-\frac{2}{3})^2

The expression on the Left Hand side is a perfect square.

(x-\frac{2}{3})^2= \frac{2}{3}+\frac{4}{9}

\Rightarrow (x-\frac{2}{3})^2= \frac{10}{9}

\Rightarrow (x-\frac{2}{3})=\pm \sqrt{\frac{10}{9}}

\Rightarrow (x)=\frac{2}{3} \pm {\frac{\sqrt{10}}{3}

Splitting the plus or minus sign gives

x=\frac{2- \sqrt{10}} {3}

or

x=\frac{\sqrt{10}+2} {3}
3 0
3 years ago
Read 2 more answers
Question 3 Please. I'm really stuck :(
Stells [14]
Let ∠RTS=∠RST = a (say)
 ∠QUA=∠QSU= b(say)
then we know , at point S, a+40+b=180. so, a+b=140 we'll use this later.

consider trianglePQR, ∠P+∠Q+∠R=180
i.e.P+(180-2b)+(180-2a)=180
P+180+180-2(a+b)=180 ⇒P+180-2(a+b)=0 ⇒P=2(140)- 180=280-180=100
hence,answer is E
7 0
2 years ago
Read 2 more answers
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