Answer:
a) 2.188
b) John's rent is not an outlier
c) His rent has to be higher than $1,235 to be an outlier
Step-by-step explanation:
The mean monthly rent of students at Oxnard University is $780 with a standard deviation of $208.
(a) John’s rent is $1,235. What is his standardized z-score?
We solve using z score formula
z = (x-μ)/σ, where
x is the raw score = $1235
μ is the population mean = $780
σ is the population standard deviation = $208
Hence,
z = 1235 - 780/208
z = 2.1875
Approximately to 3 decimal place = 2.188
(b) Is John’s rent an outlier?
No it isn't
(c) How high would the rent have to be to qualify as an outlier?
John’s rent would have to be higher than $1235
You could type in -0x+Y=-3 or 0x-Y=3 if you want x to be positive
The line of the graph has a slope of 0 so if you put it in y intercept form it would be
y=0x-3 so if you subtract x from both sides you would get -0x+Y=-3 and that would put the equation into standard form. I’m not 100% sure if it’s correct so I’m hoping it’s correct
Hello!
If there is 4 faces and 1/4 chance of any side end up face down, we just have to decrease one chance, so, the chance of the face "2" does not end up face down is equal the sum of the chances of the others faces end up face down, so, we have: 3/4.
Hugs!
