$2x+y-3=0\implies y=\stackrel{\stackrel{m}{\downarrow }}{-2} x+3 \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so we're really looking for the equation of a line with a slope of -2 and that passes through (1 , -1)

$(\stackrel{x_1}{1}~,~\stackrel{y_1}{-1})\qquad \qquad \stackrel{slope}{m}\implies -2 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-1)}=\stackrel{m}{-2}(x-\stackrel{x_1}{1}) \\\\\\ y+1=-2x+2\implies y=-2x+1$

8 0

3 years ago

Just make sure to help me out when I need it. Thx!

Mnenie [13.5K]

Answer:

okay i will

Step-by-step explanation:

5 0

3 years ago

Solve each equation.

Nostrana [21]

Answer:

13x+9=30

13x=30+9

13x=39

divide both sides by 13

x=3

12x+1=-13

12x=-13-1

12x=-14

divide both sides by 12

x=7/6

x+2+4=11

x+6=11

x=11_6

x=5

3 0

3 years ago