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BlackZzzverrR [31]
3 years ago
9

What is (x-2)^2+(y+1)^2=4^2

Mathematics
1 answer:
ehidna [41]3 years ago
6 0

Answer:

y = sqrt(16 - (x - 2)^2) - 1 or y = -sqrt(16 - (x - 2)^2) - 1

Step-by-step explanation:

Solve for y:

(x - 2)^2 + (y + 1)^2 = 16

Subtract (x - 2)^2 from both sides:

(y + 1)^2 = 16 - (x - 2)^2

Take the square root of both sides:

y + 1 = sqrt(16 - (x - 2)^2) or y + 1 = -sqrt(16 - (x - 2)^2)

Subtract 1 from both sides:

y = sqrt(16 - (x - 2)^2) - 1 or y + 1 = -sqrt(16 - (x - 2)^2)

Subtract 1 from both sides:

Answer: y = sqrt(16 - (x - 2)^2) - 1 or y = -sqrt(16 - (x - 2)^2) - 1

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2) You can divide 2000 by 4 & that gets you 500, you can then multiply that by 500 & you will get 250,000.

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