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3 years ago

What is (x-2)^2+(y+1)^2=4^2

Mathematics

1 answer:

ehidna [41]3 years ago

6 0

Answer:

y = sqrt(16 - (x - 2)^2) - 1 or y = -sqrt(16 - (x - 2)^2) - 1

Step-by-step explanation:

Solve for y:

(x - 2)^2 + (y + 1)^2 = 16

Subtract (x - 2)^2 from both sides:

(y + 1)^2 = 16 - (x - 2)^2

Take the square root of both sides:

y + 1 = sqrt(16 - (x - 2)^2) or y + 1 = -sqrt(16 - (x - 2)^2)

Subtract 1 from both sides:

y = sqrt(16 - (x - 2)^2) - 1 or y + 1 = -sqrt(16 - (x - 2)^2)

Subtract 1 from both sides:

Answer: y = sqrt(16 - (x - 2)^2) - 1 or y = -sqrt(16 - (x - 2)^2) - 1

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Answer:

The graph that includes points (-3,-3) and (0,3)

Step-by-step explanation:

In the pictures attached, the options are shown.

The equation:

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has the point-slope form, which is:

y-y₁=m(x-x₁)

where (x₁, y₁) is a point on the line and <em>m</em> is its slope. This means that (-3,-3) is on the line. To know the y-intercept of the line, we have to replace x = 0 into the equation, as follows:

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