Dimensions:
(x-3)
(x+2)
Perimater = sum of sides:
Perimeter = 14 in
Replacing:
14 in = 2 (x-3) + 2 (x+2)
Solve for x :
14 = 2x-6 + 2x + 4
combine like terms:
14 = 2x+2x-6+4
14 = 4x - 2
14+2 = 4x
16 = 4x
16/4 = x
x = 4
Dimensions:
(x-3) = 4-3 = 1
(x+2) = 4 + 2 = 6
Answer:
![x=\frac{-39}{7}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-39%7D%7B7%7D)
Step-by-step explanation:
4x+3=-9-3(x+9)
Distributing 3 over (x+9)
4x+3=-9-3x-27
Adding 3x in both sides and subtracting 3 from both sides
4x+3+3x-3=-9-3x-27+3x-3
4x+3x=-9-27-3
7x=-39
Dividing both sides by 7 we get
![\frac{7x}{7}=\frac{-39}{7}](https://tex.z-dn.net/?f=%5Cfrac%7B7x%7D%7B7%7D%3D%5Cfrac%7B-39%7D%7B7%7D)
![x=\frac{-39}{7}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-39%7D%7B7%7D)
Answer:
9 inches
Step-by-step explanation:
Given
Let;
![L = Length; W= Width](https://tex.z-dn.net/?f=L%20%3D%20Length%3B%20W%3D%20Width)
So:
![L_1=16in; W_1 = 6in](https://tex.z-dn.net/?f=L_1%3D16in%3B%20W_1%20%3D%206in)
![L_2 = 24](https://tex.z-dn.net/?f=L_2%20%3D%2024)
Required
Determine ![W_2](https://tex.z-dn.net/?f=W_2)
To do this, we make use of the following equivalent ratios
![L_1 : W_1 = L_2:W_2](https://tex.z-dn.net/?f=L_1%20%3A%20W_1%20%3D%20L_2%3AW_2)
This gives
![16 : 6= 24:W_2](https://tex.z-dn.net/?f=16%20%3A%206%3D%2024%3AW_2)
Express as fraction
![\frac{6}{16}= \frac{W_2}{24}](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B16%7D%3D%20%5Cfrac%7BW_2%7D%7B24%7D)
Multiply by 24
![W_2 = 24 * \frac{6}{16}](https://tex.z-dn.net/?f=W_2%20%3D%2024%20%2A%20%5Cfrac%7B6%7D%7B16%7D)
![W_2 = 9](https://tex.z-dn.net/?f=W_2%20%3D%209)
Answer:
x = 55
Step-by-step explanation:
In a rhombus, each diagonal bisects a pair of opposite angles.
For this parallelogram t be a rhombus, the angles with measures 2x - 40 and x + 15 must be congruent.
2x - 40 = x + 15
Subtract x from both sides.
x - 40 = 15
Add 40 to both sides.
x = 55
6+5(m+1)=26
6+5m+5=26
11+5m=26
Putting like terms together;
26-11=5m
5m=15
m=3