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3 years ago

Factorise with factor theorem: 8y^3-125x^3

1 answer:

8 0

$\\ \\ = > 8 {y}^{3} - 125 {x}^{3} \\ \\ = > {(2y)}^{3} - {(5x)}^{3} \\ \\ = > (2y - 5x)(( {2y)}^{2} + 2x \times 5y + ( {5x)}^{2} ) \\ \\ = > (2y - 5x)(4 {y}^{2} + 10xy + 25 {y}^{2} ) \: \: \: \: \: \: \: (ans)$

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HELP PLS I CAnt DO THIS

Anvisha [2.4K]

Using the two given solutions and the general absolute value function we will get:

|x + 9| = 27

<h3>Which absolute value function has that solution set?</h3>

The two solutions are:

x = 0 and x = -18.

Remember that the absolute value equation is something like:

|x - a| = b

If we want to have these solutions, then:

|0 - a| = b

|-18 -a| = b

From the first one, we have:

|-a| = b

Replacing that on the second equation we get:

|-18 -a| = |-a|

Notice that if we take a = -9, then we have:

|-18 + 9| = |+9|

|-9| = |+9|

This is true, so a = -9.

Then we find the value of b:

|18 + 9| = b = 27

Then the absolute value equation is:

|x + 9| = 27

If you want to learn more about absolute value equations, you can read.

brainly.com/question/3381225

5 0

2 years ago

Hazel traveled 796 meters by foot. She traveled 3,486 meters by car and 56,975 meters by hot air balloon. How many meters did Ha

Marina CMI [18]

Answer:

61,257

Step-by-step explanation:

796+56,975+3,486

6 0

3 years ago

Read 2 more answers

Account A and Account B both have a principal of $2,000 and an annual interest rate of 2%. No additional deposits or withdrawals

GuDViN [60]

Answer:

Account B earns more interest.

After 20 years, account B will have earned $171.89 more.

Step-by-step explanation:

Let's calculate the total for each account.

Account A:

Account A earns simple interest. We know that the principal value is $2000 and the interest rate is 2% or 0.02. We can use the simple interest formula:

$A=P(1+rt)$

Where A is the future value, P is the principal, r is the rate, and t is the time in years.

So, let's substitute 2000 for P, 0.02 for r, and 20 for t. This yields:

$A=2000(1+0.02(20))$

Multiply and add:

$A=2000(1+0.4)=2000(1.4)$

Multiply. So, the total amount of money in Account A after 20 years is:

$A=\$2800$

Since we initially deposited $2000 and our total is now $2800, this means that we earned an interest of $2800-2000=\$ 800$

Account B:

Account B earns compound interest. Like Account A, Account B has a principal value of $2000 and the interest rate is 2% or 0.02. We also know that it's compounded annually, so once per year. We can use the compound interest formula:

$B=P(1+\frac{r}{n}})^{nt}$

Where B is the future value, P is the principal, r is the rate, n is the times compounded per year, and t is the time in years.

So, let's substitute 2000 for P, 0.02 for r, n for 1 (since it's compounded annually), and t for 20. This yields:

$B=2000(1+\frac{0.02}{1})^{(1)(20)}$

Simplify this to acquire:

$B=2000(1.02)^{20}$

Evaluate. Use a calculator. So, after 20 years, the amount of money in Account B is:

$B\approx\$2971.89$

Since our principal was $2000, this means that we earned an interest of approximately $2971.89-2000=\$ 971.89$ .

So, Account A earned an interest of $800 and Account B earned an approximate interest of $971.89.

So, Account B earned more interest.

And it earned $971.89-800=\$ 171.89$ more than Account A.

And we're done!

5 0

3 years ago

14% of 60 million gallons is how many gallons?

vichka [17]

Answer:

840,000,0

Step-by-step explanation:

3 0

3 years ago

If master chief has three and a half cookies, and the arbiter has five and three quarters of a cookie, how many cookies do they

nikklg [1K]

Answer:

$9\dfrac{1}{4}$

$4\dfrac{5}{8}$

Step-by-step explanation:

The master chief has three and a half cookies i.e. $3\dfrac{1}{2} = \dfrac{7}{2}$ numbers of cookies.

Again the arbiter has five and three quarters of a cookie i.e. $5\dfrac{3}{4} = \dfrac{23}{4}$ number of cookies.

Therefore, in total there are $(\dfrac{7}{2} +\dfrac{23}{4} ) = \dfrac{37}{4} = 9\dfrac{1}{4}$ numbers of cookies.

If we divide the total number of cookies in to equal parts and distribute to then then each of them will get $\dfrac{37}{4 \times 2} = \dfrac{37}{8} = 4\dfrac{5}{8}$ numbers of cookies. (Answer)

3 0

3 years ago