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erastovalidia [21]
3 years ago
12

A scuba diver is swimming 28 feet below the water’s surface. The diver swims up slowly at a rate of 0.3 feet per second for 6 se

conds. Then they swim back down for 4 seconds at a rate of 0.3 feet per second. What is the diver’s new depth?
Mathematics
2 answers:
NISA [10]3 years ago
8 0

Answer:

27.4 feet down deep

Step-by-step explanation:

28 feet down, swins up for 0.3 feet times 6 or 1.8 feet up

leaving a total of 26.2 under the sea and he swims back down at 0.3 feet times 4 or 1.2 feet down. and the new total is 26.2 + 1.2 which equals 27.4 feet down in the deep sea

kobusy [5.1K]3 years ago
6 0

Answer:

27.4 feet

Step-by-step explanation:

.3 ft per sec for 6 sec = 1.8 feet

.3 ft per sec for 4 sec = 1.2 feet

28 - 1.8 + 1.2 = 27.4

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Answer:

{x,y}={-8,-2}

Step-by-step explanation:

 [1]    x = 2y - 4

Plug this in for variable  x  in equation [2]

  [2]    7•(2y-4) + 5y = -66

  [2]    19y = -38

Solve equation [2] for the variable  y

  [2]    19y = - 38

  [2]    y = - 2

By now we know this much :

   x = 2y-4

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Use the  y  value to solve for  x

   x = 2(-2)-4 = -8

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Step-by-step explanation:

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The football team at Riverside College plays in an old stadium that seats 50,750 people. This stadium will be demolished and a n
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