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erastovalidia [21]
3 years ago
12

A scuba diver is swimming 28 feet below the water’s surface. The diver swims up slowly at a rate of 0.3 feet per second for 6 se

conds. Then they swim back down for 4 seconds at a rate of 0.3 feet per second. What is the diver’s new depth?
Mathematics
2 answers:
NISA [10]3 years ago
8 0

Answer:

27.4 feet down deep

Step-by-step explanation:

28 feet down, swins up for 0.3 feet times 6 or 1.8 feet up

leaving a total of 26.2 under the sea and he swims back down at 0.3 feet times 4 or 1.2 feet down. and the new total is 26.2 + 1.2 which equals 27.4 feet down in the deep sea

kobusy [5.1K]3 years ago
6 0

Answer:

27.4 feet

Step-by-step explanation:

.3 ft per sec for 6 sec = 1.8 feet

.3 ft per sec for 4 sec = 1.2 feet

28 - 1.8 + 1.2 = 27.4

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snow_tiger [21]
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3 years ago
What is the answer to this decimal problem 0.32÷n=0.032
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3 years ago
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Answer:

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