Answer:
0.00375
Step-by-step explanation:
Answer:
h = 61.25 m
Step-by-step explanation:
It is given that,
The initial velocity of the ball, v = 60 m/s
It is thrown from a height of 5 feet, 
We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

Putting all the values,
.....(1)
For maximum height, put

Put t = 1.875 in equation (1)

So, the maximum height reached by the ball is 61.25 m.
That's correct but whats your question?
Multiply the second fraction by two; which gets you 5/10 + 2/10 = 7/10
Answer:
5x-6y-12=0
Step-by-step explanation:
...make y the subject y=-6/5x +2
...use the coefficient of x as the gradient,m=-6/5
...for a perpendicular line,find the negative reciprocal of the gradient,5/6
...sub into the eqn y= -1/m(x-a)+b