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3 years ago

Solve each right triangle for ABC. (Will award brainliest)

Mathematics

1 answer:

ladessa [460]3 years ago

4 0

Answer:

6.57343137182

Step-by-step explanation:

The triangle is a right triangle

1. Use Pythagorean theorem

5.5² + 3.6² = c²

2. Solve

√ 43.21

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Suppose the mean SAT verbal score is 525 with a standard deviation of 100, while the mean SAT math score is 575 with a standard

Ipatiy [6.2K]

Answer:

The mean of the combined math and verbal scores is 1100, while the standard deviation is 141.

Step-by-step explanation:

Normal variables

Normal variables have mean $\mu$ and standard deviation $\sigma$

When we add normal variables, the combined mean is the sum of both means, and the standard deviation is the square root of the sum of both variances. The distribution is still normal.

In this question:

Verbal: $\mu_{V} = 525, \sigma_{V} = 100$ .

Math: $\mu_{M} = 575, \sigma_{M} = 100$

Combined:

$\mu = \mu_{V} + \mu_{M} = 525 + 575 = 1100$

$\sigma = \sqrt{\sigma_{V}^{2}+\sigma_{M}^{2}} = \sqrt{100^2 + 100^2} = 141$

The mean of the combined math and verbal scores is 1100, while the standard deviation is 141.

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3 years ago

How to factor out the coefficient of the variable of fractions???

serg [7]

Answer:

i believe that it is 9(x-4)

Step-by-step explanation:

9x-36

36 divided by 9 = 4

9(x-4)

5 0

3 years ago

What is 50 + 9 - 6 equals

Marrrta [24]

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Which expression is equivalent to StartFraction b Superscript negative 2 Baseline Over a b Superscript negative 3 Baseline EndFr

nignag [31]

Answer:

$\frac{b^{-2}}{ab^{-3}}=\frac{b}{a}$

Step-by-step explanation:

Writing the description in algebraic translation

$\frac{b^{-2}}{ab^{-3}}$

so we have to find the expression which will be equal to $\frac{b^{-2}}{ab^{-3}}$ .

Considering the expression

$\frac{b^{-2}}{ab^{-3}}$

$\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}$

$\frac{b^{-2}}{b^{-3}}=b^{-2-\left(-3\right)}$

so the expression becomes

$=\frac{b^{-2-\left(-3\right)}}{a}$ ∵ $\frac{b^{-2}}{b^{-3}}=b^{-2-\left(-3\right)}$

$\mathrm{Subtract\:the\:numbers:}\:-2-\left(-3\right)=1$

$=\frac{b}{a}$

Therefore,

$\frac{b^{-2}}{ab^{-3}}=\frac{b}{a}$

7 0

3 years ago

Read 2 more answers

I forget how to do this problem, little help-?

jenyasd209 [6]

X=4

Please mark brainliest

4 0

2 years ago