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3 years ago

(3b-5)^2-c^2 how do I factor this using grouping?

Mathematics

1 answer:

klemol [59]3 years ago

3 0

So you see it is the difference of 2 perfect squares
a^2-b^2=(a+b)(a-b)
so
(3b-5)^2-c^2=(3b-5+c)(3b-5-c)

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4 years ago

There are 10 sweets in a bag.

Valentin [98]

Answer:

See Explanation Below

Step-by-step explanation:

Given

Total Sweets = 10

Red = 4

Green = 2

Yellow = 3

Purple = 1

Required

a & b

The question is not properly presented; however the solution is as follows;

Let P(Yellow) represent the probability of selecting a yellow sweet and n(Yellow) represent the number of Yellow sweets;

$P(Yellow) = \frac{n(Yellow)}{Total}$

$P(Yellow) = \frac{4}{10}$

$P(Yellow) = 0.4$

So, whichever letter that shows $0.4$ or $\frac{4}{10}$ is the probability of choosing a yellow sweet

Let P(Orange) represent the probability of selecting an orange sweet and n(Orange) represent the number of orange sweets;

Since, there's no orange sweet in the bag;

$n(Orange) = 0$

$P(Orange) = \frac{n(Orange)}{Total}$

$P(Orange) = \frac{0}{10}$

$P(Orange) = 0$

In probability; opposite probabilities add up to 1;

Let P(Not\ Orange) represent the probability of choosing a sweet that is not orange

$P(Not\ Orange) + P(Orange) = 1$

Substitute $P(Orange) = 0$

$P(Not\ Orange) + 0 = 1$

$P(Not\ Orange) = 1$

So, whichever letter that shows 0 is the probability of choosing a sweet that is not orange

6 0

3 years ago