Answer:
radius ≈ 15.5
Step-by-step explanation:
the radius is RS
the angle between a tangent and the radius at the point of contact is 90°
then Δ RST is a right triangle
using Pythagoras' identity in the right triangle.
the square on the hypotenuse is equal to the sum of the squares on the other 2 sides , then
RS² + ST² = RT² ( substitute values )
RS² + 7² = 17²
RS² + 49 = 289 ( subtract 49 from both sides )
RS² = 240 ( take square root of both sides )
RS = ≈ 15.5 ( to 1 dec. place )
B^-2 / b^-3 = b^(-2-(-3) = b^1 = b
answer is d
i would solve 4x-y =3 for y because the coefficient for y is 1
subtract 4x from each side
-y = -4x+3
divide by -1
y = 4x-3
Is something missing
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