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ira [324]
3 years ago
8

Solve x+y=9,x-y=5 by graphical method

Mathematics
1 answer:
Furkat [3]3 years ago
5 0
The answer should be (7,2)
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PLEASE HELP ME!!!!! (Urgent)
defon

Answer:

f(x)=x^5-6x^4+14x^3-24x^2+40x

Step-by-step explanation:

<u>Given information</u>:

  • Polynomial function with real coefficients.
  • Zeros: 0, 2i and (3+i).

For any complex number   z=a+bi , the complex conjugate of the number is defined as  z^*=a-bi.  

If f(z) is a polynomial with real coefficients, and z₁ is a root of f(z)=0, then its complex conjugate z₁* is also a root of f(z)=0.

Therefore, if f(x) is a polynomial with real coefficients, and 2i is a root of f(x)=0, then its complex conjugate -2i is also a root of f(x)=0.

Similarly, if (3+i) is a root of f(x)=0, then its complex conjugate (3-i) is also a root of f(x)=0.

Therefore, the polynomial in factored form is:

f(x)=ax(x-2i)(x-(-2i))(x-(3+i))(x-(3-i))

f(x)=ax(x-2i)(x+2i)(x-3-i)(x-3+i)

As we have not been given a leading coefficient, assume a = 1:

f(x)=x(x-2i)(x+2i)(x-3-i)(x-3+i)

Expand the polynomial:

f(x)=x(x^2+2ix-2ix-4i^2)(x^2-3x+xi-3x+9-3i-xi+3i-i^2)

f(x)=x(x^2-4i^2)(x^2-6x+9-i^2)

f(x)=x(x^2-4(-1))(x^2-6x+9-(-1))

f(x)=x(x^2+4)(x^2-6x+10)

f(x)=(x^3+4x)(x^2-6x+10)

f(x)=x^5-6x^4+10x^3+4x^3-24x^2+40x

f(x)=x^5-6x^4+14x^3-24x^2+40x

8 0
2 years ago
Read 2 more answers
Solve the inequality. g + 2 – 2(g – 16) &gt; 0
Fynjy0 [20]
If you are looking for g then the answer is g<34
3 0
3 years ago
Read 2 more answers
the population of a local species of dragonfly can be found using an infinite geometric series where a1=30 and the common ratio
diamong [38]
The sum of any geometric sequence (if it converges, r^2<1) is of the form:

s(n)=a(1-r^n)/(1-r), a=initial term, r=common ratio, n=number of terms...

s(n)=30(1-0.4^n)/(0.6)

s(n)=50(1-0.4^n)

Since r<1 the sum of the infinite series is just:

s=50
7 0
4 years ago
How do you solve y=2x+7; 3x-y=-9 using substitution method. Explain please!!
eduard
The y's value is given in the first equation. y=2x+7 . Now to solve, we will, plug it's value in the second equation.

3x-(2x+7)=-9\\ \\ 3x-2x-7=-9\\ \\ x=-9+7\\ x=-2\\

Now we have x's value, we will plug it's value in the first equation.(We can plug it in the second one too, but plugging it the first one will make it easier.)

x=-2\\ y=2x+7\\ y=2\cdot -2+7\\ y=-4+7\\ y=3




6 0
4 years ago
Read 2 more answers
Which of the point-slope equations below are correct for the line that passes through points (-4,-14) and (1,3)?
Scrat [10]
(-4,-4)(1,3)
slope = (3 - (-4) / (1 - (-4)
slope = (3 + 4) / (1 + 4) = 7/5

y - y1 = m(x - x1)...using (-4,-4)
slope(m) = 7/5
y - (-4) = 7/5(x - (-4) =
y + 4 = 7/5(x + 4) <==here is one

y - y1 = m(x - x1)..using (1,3)
slope = 7/5
y - 3 = 7/5(x - 1) <== here is the other one
4 0
3 years ago
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