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Julli [10]
3 years ago
13

In the circle shown, AB is tangent to circle o at point and OC is a radius

Mathematics
1 answer:
Vlada [557]3 years ago
8 0

Answer:

A. \overline{OC} \perp \overline{AB}

Step-by-step explanation:

According to tangent theorem, a tangent is formed when the radius of a circle is perpendicular to the line, meeting at a point around the circle, such that the tangent line would be perpendicular to the radius of the circle with a center.

Given that \overline{AB} is a tangent of the circle O, at a point C, and \overline{OC} is a radius, therefore, it follows that:

\overline{OC} \perp \overline{AB}.

This means the radius of the circle is perpendicular to the tangent formed at point C.

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2 years ago
Marina walks from the police station at (-10, -4) to her friend Marissa’s house at (3, -8). She stops half way at a fast food re
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\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -10}}\quad ,&{{ -4}})\quad 
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3 years ago
Find the distance between the points (3, –8) and (0, –9).
nadezda [96]

The formula for distance between two points is:

\sqrt{(x_{2} -x_{1})^{2} + (y_{2} -y_{1})^{2}}

In this case:

x_{2} =0\\x_{1} =3\\y_{2} =-9\\y_{1} =-8

^^^Plug these numbers into the formula for distance like so...

\sqrt{(0-3)^{2} + (-9 - (-8))^{2}}

To solve this you must use the rules of PEMDAS (Parentheses, Exponent, Multiplication, Division, Addition, Subtraction)

First we have parentheses. Remember that when solving you must go from left to right

\sqrt{(0-3)^{2} + (-9-(-8))^{2}}

0 - 3 = -3

\sqrt{(-3)^{2} + (-9-(-8))^{2}}

-9 - (-8) = -1

\sqrt{(-3)^{2} + (-1)^{2}}

Next solve the exponent. Again, you must do this from left to right

\sqrt{(-3)^{2} + (-1)^{2}}

(-3)² = 9

\sqrt{9 + (-1)^{2}}

(-1)² = 1

\sqrt{(9+1)}

Now for the addition

\sqrt{(9+1)}

9 + 1 = 10

√10 <<<This can not be further simplified so this is your exact answer

Your approximate answer would be about 3.16

***Remember that the above answers are in terms of units

Hope this helped!

~Just a girl in love with Shawn Mendes

4 0
3 years ago
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