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3 years ago

What is the width of a rug that is 36 1/4 square feet and 8 3/4 wide

Mathematics

1 answer:

blondinia [14]3 years ago

8 0

Answer: $4\frac{1}{7} ft$

Step-by-step explanation:

Area (A): $36\frac{1}{4} = \frac{4(36)+1}{4} = \frac{144+1}{4} = \frac{145}{4}$

Length (L): $8\frac{3}{4} = \frac{4(8)+3}{4} = \frac{32+3}{4} = \frac{35}{4}$

width (w): W

A = L x W

$\frac{145}{4}$ = $\frac{35}{4}$ x W

$(\frac{4}{35})$ $\frac{145}{4}$ = $(\frac{4}{35})$ $\frac{35}{4}$ x W

$\frac{4(145)}{35(4)} = \frac{145}{35} = \frac{5(29)}{5(7)} = \frac{29}{7} = W$

$\frac{29}{7} = \frac{7(4) + 1}{7} = 4\frac{1}{7}$

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A rectangle has a height of 5m^4 and a width of m^2-2m-1.

In-s [12.5K]

Answer:

area of the rectangle = 5(m⁶ - 2m⁵ - m⁴) or 5m⁴(m² - 2m - 1)

Step-by-step explanation:

The rectangle has a height of 5m⁴ and the width is m² - 2m - 1.The area of the rectangle is the product of the width and the height.

width = m² - 2m - 1

height = 5m⁴

area of rectangle = 5m⁴ × (m² - 2m - 1)

area of rectangle = 5m⁴(m² - 2m - 1)

area of the rectangle = 5m⁶ - 10m⁵ - 5m⁴

area of the rectangle = 5(m⁶ - 2m⁵ - m⁴)

The area of the entire rectangle can be expressed as 5(m⁶ - 2m⁵ - m⁴) or 5m⁴(m² - 2m - 1)

8 0

2 years ago

Read 2 more answers

The Graph describes the water level of creek after a rainstorm which best describes the domain in context?

belka [17]

The domain of a function are its possible input values

The domain of the function is (b) all real numbers greater than or equal to 0.

From the graph, we have the following observations

t represents time (it is plotted on the x-axis)
t starts at 0
t has no end

The above observations imply that; the domain starts from 0

Hence, the domain of the function is the set of all real numbers greater than or equal to 0.

Read more about domain at:

brainly.com/question/2709928

5 0

1 year ago

Someone plz help I already know the answer put how can I put the diagram can you guys help me can u put the picture how u did it

Oliga [24]

Answer:

therws this random chart from the internet, I think that's what they want, but not sure

8 0

2 years ago

Mrs. Davis went to a produce market to buy bananas and strawberries. She spent $8.00. If the bananas were $0.50 per pound, and t

9966 [12]

9514 1404 393

Answer:

4 pounds

Step-by-step explanation:

Let b represent the pounds of bananas Mrs. Davis bought. The weight of strawberries would be (7-b) and their cost would be 4×0.50 = 2.00 per pound. Her total purchase was ...

0.50b + 2.00(7 -b) = 8.00

-1.50b +14 = 8 . . . . simplify

6 = 1.50b . . . . . . add 1.50b -8

4 = b . . . . . . . . divide by 1.50

Mrs. Davis bought 4 pounds of bananas.

7 0

2 years ago

(High points) please solve with explanation

AysviL [449]

Answer:

The area and the perimeter of the picture are:

Area = 160 cm^2
Perimeter = 67.31 cm

Step-by-step explanation:

To find the area of that figure, you can find the area how if it was a rectangle and next subtract the area of the triangle in the upper part. The area of a rectangle could be found by the next formula:

Area of a rectangle = base * height

As you can see in the picture, the base is 16 cm and the height is 12 cm, then we replace in the formula:

Area of a rectangle = 16 cm * 12 cm
Area of a rectangle = 192 cm^2

Now, we calculate the area of the triangle to subtract to the area we found and obtain the real area, the formula to obtain the area of a triangle is:

Area of a triangle = (base * height) / 2

The height of the triangle is 8 cm, and the base is 8 cm too, because you subtract to the base of the rectangle (16 cm) the measurements in the upper part (16 - 4 - 4 = 8), Now, we replace in the formula:

Area of a triangle = (8 cm * 8 cm) / 2
Area of a triangle = (64 cm^2) / 2
Area of a triangle = 32 cm^2

We subtract to the found area:

Area of the picture = 192 cm^2 - 32 cm^2
Area of the picture = 160 cm^2

To find the perimeter, you must add all the sides of the picture, but, as you can see, there is a side that doesn't have the measurent, this is the hypotenuse of the triangle used before, but how we know the other sides, we can use Pythagorean theorem: