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Ber [7]
3 years ago
7

Question 11

Mathematics
1 answer:
Svetlanka [38]3 years ago
7 0

Answer:

The perimeter of the enlarged rectangle is 36 inches.

Step-by-step explanation:

Perimeter of an enlarged figure:

To find the perimeter of an enlarged figure, we multiply the perimeter of the original figure by the scale factor.

In this question:

Perimeter of the original rectangle: 12 inches

Scale factor: 3

Perimeter of the enlarged rectange:

12*3 = 36 inches

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Complete the process of solving the equation.
boyakko [2]

Answer:

t = 1

Step-by-step explanation:

5t + 8 = 13

Subtract 8 from both sides

5t + 8 - 8 = 13 - 8

5t = 5

Divide both sides by 5

5t/5 = 5/5

t = 1

Check:

5t + 8 = 13

5(1) + 8 = 13

5 + 8 = 13

6 0
3 years ago
Write an equation parallel to 2x+5y=15 that passes through the point (-10,1).
shusha [124]
2x + 5y = 15
5y = -2x + 15
y = -(2/5)x + 3

y = mx + b
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So the equation of the line would be:
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3 0
4 years ago
An automobile purchased for 22000 is worth 2500 after 5 years what’s the value 3 years after it is purchased
ohaa [14]

(17,000-2,500)/5=14,500/5=$2,900 is the annual depreation.

17,000-2,900*3

17,000-8,700=$8,300 value after 3 years.

6 0
3 years ago
1)
Serjik [45]

\qquad \purple{\twoheadrightarrow\bf  2cos^2A = 1 + cos2A }

\qquad \purple{\twoheadrightarrow\bf  a^3 +b^3 = (a+b)^3 -3ab(a+b)}

\qquad \purple{\twoheadrightarrow\bf  2 sinA cosA = sin2A}

________________________________________

1)

\qquad \twoheadrightarrow\bf L.H.S

\qquad \pink{\twoheadrightarrow\bf cos^4 x}

\qquad \twoheadrightarrow\sf \dfrac{1}{4} (2cos^2x)^2

\qquad \twoheadrightarrow\sf \dfrac{1}{4}(1+cos2x)^2

\qquad \twoheadrightarrow\sf \dfrac{1}{4}(1+2cos2x+cos^22x)

\qquad \twoheadrightarrow\sf \dfrac{1}{4}+\dfrac{1}{2}cos2x+\dfrac{1}{8}\times 2cos^22x

\qquad \twoheadrightarrow\sf \dfrac{1}{4}+\dfrac{1}{2}cos2x+\dfrac{1}{8}\times(1+cos4x)

\qquad \pink{\twoheadrightarrow\bf \dfrac{1}{4}+\dfrac{1}{2}cos2x+\dfrac{1}{8}\times cos4x}

\qquad \twoheadrightarrow\bf R.H.S

______________________________________

2)

\qquad \twoheadrightarrow\bf L.H.S

\qquad \pink{\twoheadrightarrow\bf cos^6\theta +sin^6\theta }

\qquad \twoheadrightarrow\sf (cos^2\theta)^3 +(sin^2\theta)^3

\twoheadrightarrow\sf (cos^2\theta +sin^2\theta)^3 -3cos^2\theta sin^2\theta (cos^2\theta +sin^2\theta)

\qquad \twoheadrightarrow\sf 1-3\times \dfrac{1}{4}\times 4(sin\theta cos\theta) ^2

\qquad \twoheadrightarrow\sf 1-\dfrac{3}{4}(2sin\theta cos\theta) ^2

\qquad \pink{\twoheadrightarrow\sf 1-\dfrac{3}{4}sin^22\theta}

\qquad \twoheadrightarrow\bf R.H.S

3 0
3 years ago
I’m on exam so answer quick please
GarryVolchara [31]

Answer:

13/36 or 0.361

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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