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KiRa [710]
3 years ago
10

On Monday it snowed a certain amount. On Tuesday it snowed 3 times as much as Monday. On Wednesday it snowed twice as much as Mo

nday. On Thursday it snowed the same amount as Monday, write an expression for each situation.
Mathematics
1 answer:
liubo4ka [24]3 years ago
8 0

Answer:

Expression for each situation:

Given, On Monday it snowed a certain amount.  

Let the amount of snow on Monday be n.

On Tuesday it snowed 3 times as much as Monday.  

Then, \text{{amount of snow on Tuesday}}= \text{{amount of snow on Monday}}\times 3

amount of snow on Tuesday = 3 x n = 3n

On Wednesday it snowed twice as much as Monday.  

Then,\text{{amount of snow on wednesday}}= \text{{amount of snow on Monday}}\times 2

amount of snow on Wednesday = 2 x n = 2n

On Thursday it snowed the same amount as Monday,  

Then, amount of snow on Thursday = amount of snow on Monday  

amount of snow on Thursday = n

Hence, we have written expressions for each situation.

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4 years ago
1. Rosie orders dessert at the cafe. The total bill is $50. She tips the waiter 10%.
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Answer:

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3 years ago
Which expression has a value that is equivalent to the given expression when n = 8?
mrs_skeptik [129]

Q1.

Put the value of n = 8 to the expressions:

2n + 10 → 2(8) + 10 = 16 + 10 = 26

A: 3n → 3(8) = 24 ≠ 26

B: 2(n + 5) → 2(8 + 5) = 2(13) = 26   :)

C: n² + 5 → 8² + 5 = 64 + 5 = 69 ≠ 26

D: 10n + 2 → 10(8) + 2 = 80 + 2 = 82 ≠ 26

<h3>Answer: B: 2(n + 5)</h3>

Q2.

x = 3, y = 2

L = 5y² - 2x → L = 5(2)² - 2(3) = 5(4) - 6 = 20 - 6 = 14

R = x² + ... → R = 3² + ... = 9 + ...

A: x² + x → 9 + 3 = 12  NOT

B: x² + y → 9 + 2 = 11   NOT

C: xy → 9 + (3)(2) = 9 + 6 = 15 YES

D: 2y → 9 + (2)(2) = 9 + 4 = 13   NOT

5y² - 2x < x² + xy

L = 14, R = 15, L < R    CORRECT

<h3>Answer: C: xy</h3>

Q3.

3 + 6² = 3 + 36 = 39

A: 3³ + 12 = 27 + 12 = 39  NOT

B: 5² + 4² = 25 + 16 = 41 > 39    YES

C: 2³ + 5² + 6 = 8 + 25 + 6 = 39    NOT

D: 2³ + 14 + 17 = 8 + 14 + 17 = 39    NOT

<h3>Answer: B: 3 + 6² < 5² + 4²</h3>
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3 years ago
What - |3| math evaluate absolute value
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The answer is -3, because the negative sign is outside of the absolute value. If the problem looked like this |-3|, then the answer would be 3. To clarify, your answer is -3.
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3 years ago
Select the correct answer.
bezimeni [28]
I think it would be A
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3 years ago
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