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Diano4ka-milaya [45]
3 years ago
6

Explain why it might be easier to solve the multiplication problem by changing it from this: 5×87×2, to this: 5×2×87. Use a prop

erty of multiplication to justify your reasoning.
Mathematics
2 answers:
mart [117]3 years ago
8 0

Answer:

It makes the calculation easy and quick.

Step-by-step explanation:

  • <em>Commutative Property of multiplication</em>
  • <em>The product of two or more real numbers is not affected by the order in which they are being multiplied. In other words, real numbers can be multiplied in any order because the product remains the same. </em>

<u>When you multiply as it is given:</u>

  • 5×87×2=870
  • Step 1)  5×87 = 435
  • Step 2) 435×2 = 870

<u>Using the commutative property makes it much easier:</u>

  • 5×2×87 = 870
  • Step 1) 5×2 = 10
  • Step 2) 10* 87 = 870
dolphi86 [110]3 years ago
8 0

Answer:

see below.

Step-by-step explanation:

its a commutative property of multiplication.

it doesn't matter in order or not... the result will always be the same.

form your example 5×87×2, if you use a calculator it doesn't matter which number you start.

say 2 x 87 x 5 = 870

or 87 x 5 x 2 = 870

or 5 x 2 x 87 = 870

see the results are all the same no matter which way you go.

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4 years ago
Two candidates face each other in an election. The Democratic candidate is supported by 46% of the population, and the Republica
7nadin3 [17]

Answer:

27.98% probability that less than half of them (3 or fewer) would support the Republican candidate

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they support the Republican candidate, or they do not. The people are chosen at random, which means that the probability of them supporting the republican candidate is independent from other people. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

The Republican candidate is supported by 54%. This means that p = 0.54

Suppose you run a poll of 8 people (randomly choose 8 people). What is the probability that less than half of them (3 or fewer) would support the Republican candidate?

This is P(X \leq 3) when n = 8.

So

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{8,0}.(0.54)^{0}.(0.46)^{8} = 0.0020

P(X = 1) = C_{8,1}.(0.54)^{1}.(0.46)^{7} = 0.0188

P(X = 2) = C_{8,2}.(0.54)^{2}.(0.46)^{6} = 0.0774

P(X = 3) = C_{8,3}.(0.54)^{3}.(0.46)^{5} = 0.1816

So

P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0020 + 0.0188 + 0.0774 + 0.1816 = 0.2798

27.98% probability that less than half of them (3 or fewer) would support the Republican candidate

3 0
4 years ago
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