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Kamila [148]
3 years ago
7

The graph of F(x), shown below, has the same shape as the graph of G(x) = x2, but it is shifted to the left 3 units. What is its

equation?

Mathematics
2 answers:
Tems11 [23]3 years ago
6 0

Answer:

f(x) = (x - 3)²

Step-by-step explanation:

If the function given below is g(x) = x²

Then we have to find the function f(x) which is same as g(x) but shifted 3 units left.

As we know in the given equation f(x) = (a + x)²+ k, x defines the shift of the function and and k defines the shift of a graph on y-axis upwards or downwards.

Here the graph is shifted left so the value of x will be (-3) which defines the shifting of 3 left on x-axis.

Therefore the new function will be f(x) = (x - 3)²

Korvikt [17]3 years ago
5 0

Answer:

F(x)=(x+3)^2

Step-by-step explanation:

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A square has a perimeter of 36x - 12. Which expression represents one side of the<br> square?
valina [46]

Answer:

9x - 3

Step-by-step explanation:

Hello!

A square has 4 sides.

We can factor out 4 from the expression to find the value of one side.

Factor:

  • 36x - 12
  • 4(9x) - 4(3)
  • 4(9x - 3)

This means that each side of the square is 9x - 3 units long.

6 0
2 years ago
Write the expression that appears under the radical symbol in the quadratic formula. what is the quality called? what can it be
ira [324]
This expression is called the Discriminant, also shown as Δ.
It is equal to b² - 4ac. This is a very important part of the quadratic formula as it determines whether x will have two values, one repeated value or no real values. Here are a few examples.

a) x² - 2x - 1. a is equal to 1 since 1x² = x². b = -2, c = -1
The discriminant will be (-2)² - 4×1×-1 = 4 + 4 = 8.
Since Δ > 0, there are two x values. Graphed, the parabola sinks below the x axis.

b) x². a = 1, b = 0 (0x = 0), c = 0
The discriminant will be 0² - 4×1×0 = 0 - 0 = 0.
Since Δ = 0, there is only one x value. Graphed, the parabola touches the x axis at only one point.

c) x² + 1. a = 1, c = 1.
The discriminant will be 0² - 4×1×1 = 0 - 4 = -4
Since Δ < 0, there are no real x values. Graphed, the parabola floats above the x axis.

Hope this helps!
8 0
3 years ago
Solve each inequality 1 &lt; x -2
ludmilkaskok [199]
Add 2 to both sides...x>3
7 0
3 years ago
Read 2 more answers
How to evaluate the expression
noname [10]
[(-72) \div (-2)]^3 - (-7) \times (-10)

= [36]^3 - (-7) \times (-10)

=46656 - (-7) \times (-10)

=46656 - (70)

=46586

-------------------------------------


2^3 - 9 \times (2 - 4)

= 8 - 9 \times (-2)

= 8 - (-18)

= 8 + 18

= 26

4 0
3 years ago
Use a calculator to solve the following equation for θ on the interval [−90∘,90∘]. Sin(θ)=34
exis [7]

The value of θ from the given equation is 48.59degrees

<h3>Trigonometry identity</h3>

Given the trigonometry function

Sin(θ)=3/4

We are to find the value of theta that will make the expression true

Take the arcsin of both sides

arcsin Sin(θ)= arcsin(3/4)

θ = arcsin(3/4)

θ = 48.59

Hence the value of θ from the given equation is θ = 48.59 defense

Learn more on trig identity here:brainly.com/question/7331447

4 0
2 years ago
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