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Kamila [148]
3 years ago
7

The graph of F(x), shown below, has the same shape as the graph of G(x) = x2, but it is shifted to the left 3 units. What is its

equation?

Mathematics
2 answers:
Tems11 [23]3 years ago
6 0

Answer:

f(x) = (x - 3)²

Step-by-step explanation:

If the function given below is g(x) = x²

Then we have to find the function f(x) which is same as g(x) but shifted 3 units left.

As we know in the given equation f(x) = (a + x)²+ k, x defines the shift of the function and and k defines the shift of a graph on y-axis upwards or downwards.

Here the graph is shifted left so the value of x will be (-3) which defines the shifting of 3 left on x-axis.

Therefore the new function will be f(x) = (x - 3)²

Korvikt [17]3 years ago
5 0

Answer:

F(x)=(x+3)^2

Step-by-step explanation:

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Answer:

f^{-1}(x)=9x-18

Step-by-step explanation:

we have

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Let

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y=\frac{1}{9}x+2

Exchange variables x for y and y for x

x=\frac{1}{9}y+2

Isolate the variable y

x-2=\frac{1}{9}y

y=9(x-2)

y=9x-18

Let

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f^{-1}(x)=9x-18 -------> inverse function

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The vertices of right triangle ABC are A(−1, 2), B(3, 2), and C(3, 7). The triangle is dilated with a scale factor of 2. Estimat
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a 1ft long piece of wire needs to be divided into two pieces which will form the shape of a circle and a square. Determine the l
yan [13]

Answer:

Length of wire for circle is 0.44 ft

Length of wire for square is 0.56 ft

Step-by-step explanation:

Let x is circumference of the circle

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r =  (x/2.π)

Find the area of the circle

a =  π(x/2π)^2

a =  π(x^2/4π^2)

Cancel π

a =  x^2/4π

Find the area of the square:

a =  (1-x/4)^2

a =  (1-2x+x^2)/16

Total area

A =  (x^2/4π)+(1-2x+x^2/16)

A = 4x^2+3.142-6.284x+3.142x^2

A = 7.142x^2-6.284x+3.142

Find the axis of symmetry [x = -b/(2a)]

x =  -(-6.284)/{2.(7.142)}

x =  6.284/14.284

x = 0.44 ft, the piece of wire creating a circle

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1 - 0.44 = 0.56 ft, the piece of wire creating the square

These lengths should give minimum area of the circle and square together

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Answer:

y = 2

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Given

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