I=k/d^2
4=k/d^2 and 1=k/64 so if we divide the first by the second we get:
4/1=(k/d^2)/(k/64)
4=(k/d^2)*(64/k)
4=64/d^2
d^2=64/4
d^2=16
d=4 meters
Minimum required sample size for a desired margin of error and confidence level when it is a proportion problem: n = (z2÷margin of error2)*p-hat*q-hat
The maximum value of p-hat*q-hat occurs where p-hat = .5 (found by taking the derivative of (p-hat)*(1-p-hat) and setting it equal to 0 to find the maximum. n = ( 2.5762( for 99% confidence interval)÷.0482 )*.5*.5 = 720.028 or 721
14 I think.You would subtract 15-8 which is 7 and then add 7 which is 14
Answer:
You set up an equation, using the trig function "tan" to find half of the roof (the equation would be tan(24) = 3.5/x, where x = 1/2 roof width)
Step-by-step explanation:
That would be the first step.
You solve the equation for x, and then multiply x by 2 to get the width of the roof.