Each kind of computer users have different knowledge, needs and requirements. For example there is a difference between the computer knowledge of developers and users without <span>technical experience. Because of this, but also why they need and use computers, and what tools they need, design consideration need to change for each kind of computer users.</span>
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<u>Extensible Markup Language (XML)</u> is a markup language designed to transport and store data on the Web.
Explanation:
- Extensible Markup Language (XML) is a markup language that defines a set of rules for encoding documents in a format that is both human-readable and machine-readable
- Extensible means that the language is a shell, or skeleton that can be extended by anyone who wants to create additional ways to use XML.
- Markup means that XML's primary task is to give definition to text and symbols.
- It is a textual data format with strong support, Unicode for different human languages.
- Extensible Markup Language (XML) is used to describe data.
- The design goals of XML emphasize simplicity, generality, and usability across the Internet.
- It is a text-based markup language derived from Standard Generalized Markup Language (SGML).
Answer: Information
Explanation: Information flows consist of data related to demand, shipments, orders, returns, and schedules, as well as changes in any of these data.
Answer:
#include<bits/stdc++.h>
using namespace std;
int sumOfinteger(int );
// Returns sum of all digits in numbers from 1 to n
int sumOfintegersFrom1ToN(int n) {
int result = 0; // initialize result
// One by one compute sum of digits in every number from
// 1 to n
for (int x = 1; x <= n; x++)
result += sumOfinteger(x);
return result;
}
// A utility function to compute sum of digits in a
// given number x
int sumOfinteger(int x) {
int sum = 0;
while (x != 0) {
sum += x %10;
x = x /10; }
return sum; }
// Driver Program
int main() {
int n ;
cout<<"enter a number between 1 and n : ";
cin>>n;
cout << "Sum of digits in numbers from 1 to " << n << " is " << sumOfDigitsFrom1ToN(n);
return 0; }
