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iragen [17]
3 years ago
8

Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2 h, and Car B traveled the dista

nce in 1.5 h. Car B
traveled 15 mph faster than Car A.

How fast did Car B travel?
Mathematics
1 answer:
Yuki888 [10]3 years ago
6 0
d=v \cdot t
d - distance
v - speed
t - time

Car A:
v_1 \\
t_1=2 \\
d_1=v \cdot 2=2 v

Car B:
15 mph faster than car A
v_2=v_1+15 \\ t_2=1.5 \\ d_2= (v_1+15) \cdot 1.5=1.5v_1 + 22.5

Both cars traveled equal distances:
d_1=d_2 \\
2v_1 = 1.5v_1+22.5 \\
2v_1-1.5v_1=22.5 \\
0.5v_1=22.5 \\
v_1=45 \\ v_2=45 + 15 =60

Car B traveled at the speed of 60 mph.
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Answer:

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if one side a the little white hexagon equals 6 ft;

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Paul [167]

Hello from MrBillDoesMath!

Answer:

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Discussion:

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x^4 - 25 =   (x^2+5)(x + sqrt(5)) (x - sqrt(5))       => factor x^2 + 5

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