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3 years ago

Identify the scale factor.

Mathematics

2 answers:

Elenna [48]3 years ago

8 0

3 wouldn’t be sufficient amount of info.
I’d say 3:1.

Xelga [282]3 years ago

5 0

Answer:

Step-by-step explanation:

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What is the equation for this line ?

Fynjy0 [20]

Answer:

$y = -\frac{1}{3}x + 5$

Step-by-step explanation:

y = mx + b

Let's start with where the line crosses the y axis. We can see it crosses at 5.

So b = 5.

Let's try another point to figure out m, (3,4).

4 = 3m + 5

3m = -1

m = $-\frac{1}{3}$

4 0

3 years ago

Read 2 more answers

Please assist me with the power of i(imaginary)

kolezko [41]

Let's raise i to various powers starting with 0,1,2,3...

i^0 = 1

i^1 = i

i^2 = ( sqrt(-1) )^2 = -1

i^3 = i^2*i = -1*i = -i

i^4 = (i^2)^2 = (-1)^2 = 1

i^5 = i^4*i = 1*i = i

i^6 = i^5*i = i*i = i^2 = -1

We see that the pattern repeats itself after 4 iterations. The four items to memorize are

i^0 = 1

i^1 = i

i^2 = -1

i^3 = -i

It bounces back and forth between 1 and i, alternating in sign as well. This could be one way to memorize the pattern.

To figure out something like i^25, we simply divide the exponent 25 over 4 to get the remainder. In this case, the remainder of 25/4 is 1 since 24/4 = 6, and 25 is one higher than 24.

This means i^25 = i^1 = i

Likewise,

i^5689 = i^1 = i

because 5689/4 = 1422 remainder 1. The quotient doesn't play a role at all so you can ignore it entirely

8 0

3 years ago

WILL MARK BRAINLIEST!!! Given p(x)=x3−4x2+15x+k and the remainder of the division of p(x) by (x+1) is equal to −8, what is the r

balandron [24]

Use the polynomial remainder theorem. If $p(x)$ is a polynomial of degree $n>1$ , then we can divide by a linear term $x-c$ to get a quotient $q(x)$ and remainder $r(x)$ of the form

$\dfrac{p(x)}{x-c}=q(x)+\dfrac{r(x)}{x-c}\iff p(x)=(x-c)q(x)+r(x)$

Then when $x=c$ , we get $p(c)=r(c)$ . In other words, the value of $p(x)$ at $x=c$ tells you the value of the remainder upon dividing $p(x)$ by $x-c$ .

So given that $p(x)=x^3-4x^2+15x+k$ , and the remainder upon dividing $p(x)$ by $x+1$ is -8, we know that $r(-1)=-8$ , so

$\dfrac{x^3-4x^2+15x+k}{x+1}=q(x)-\dfrac8{x+1}$
$\dfrac{x^3-4x^2+15x+k+8}{x+1}=q(x)$

Since $q(x)$ is a polynomial (not a rational expression), then we know that $x+1$ divides $x^3-4x^2+15x+k+8$ exactly. In particular, the remainder term of this quotient is 0. We can use long or synthetic division to determine $q(x)$ . I prefer typing out the work for synthetic division:

-1   |   1   -4   15    k + 8
.     |        -1     5       -20
- - - - - - - - - - - - - - - - - -
.     |   1   -5    20    k - 12

The remainder here has to be 0, so $k-12=0\implies k=12$ .

Finally, we can get the remainder upon dividing $p(x)$ by $x-1$ by evaluating $p(1)$ , which gives $p(1)=24$ .

6 0

3 years ago

Read 2 more answers

Deshawn won 95 pieces of gum playing hoops at the county fair. At school he gave four to every student in his math class. Write

wlad13 [49]

Answer:

95 - 4x

Step-by-step explanation:

where x is the number of students in the class

5 0

4 years ago

Help please!!!!!!!!!!!