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3 years ago

What is the degree of the monomaniacal 4x7y3

Mathematics

1 answer:

NeTakaya3 years ago

6 0

The degree is 10 because you had the exponents 7 + 3

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Finding a polynomial of a given degree with given zeros

galben [10]

Since f(x) is a polynomial with 3rd degree, then it will have 3 roots (zeroes)

One of them is real and the other two are complex conjugate roots

Since the real root is 4, then

x = 4

Since the complex root is (1 - i), then

The other root will be the conjugate of it (1 + i)

x = (1 - i)

x = (1 + i)

To find f(x) we will multiply the three factors of it

We can get the factors from the zeroes

$x=4$

Subtract 4 from both sides

$\begin{gathered} x-4=4-4 \\ x-4=0 \end{gathered}$

The first factor is (x - 4)

$\begin{gathered} x=1-i \\ x-(1-i)=(1-i)-(1-i) \\ x-1+i=0 \end{gathered}$

The second factor is (x - 1 + i)

The third factor is (x - 1 - i)

$f(x)=(x-4)(x-1+i)(x-1-i)$

We will multiply them to find f(x)

$\begin{gathered} (x-1+i)(x-1-i)= \\ x^2-x-ix-x+1+i+ix-i-(i^2)= \\ x^2-2x+1-(-1)= \\ x^2-2x+1+1= \\ x^2-2x+2 \end{gathered}$

Multiply it by (x - 4)

$\begin{gathered} f(x)=(x-4)(x^2-2x+2) \\ f(x)=x^3-2x^2+2x-4x^2+8x-8 \\ f(x)=x^3-6x^2+10x-8 \end{gathered}$

The answer is

$f(x)=x^3-6x^2+10x-8$

5 0

1 year ago

Simplest form equivalent to 3y + y + 2y - 4y

bixtya [17]

Answer:

4y+6y

Step-by-step explanation

PUT ME THE BRAINLIEST PLEASE

7 0

3 years ago

Read 2 more answers

I really need help I would appreciate it if someone could help me

sleet_krkn [62]

Answer:

a) The vertex of the graph is $(h,k) = (0, 31)$ , b) $a = -16$ , c) The equation of the parabola is $f(t) = -16\cdot t^{2}+31$ .

Step-by-step explanation:

a) The tennis ball experiments a free fall, that is, an uniform accelerated motion due to gravity and in which effects from Earth's rotation and air viscocity are negligible. The height of the ball in time is represented by a second order polynomial. Hence, the vertex of the parabola is the initial point highlighted in graph.

The vertex of the graph is $(h,k) = (0, 31)$ .

b) If we know that $(h,k) = (0, 31)$ , $f(t) = a\cdot (t-h)^{2} + k$ and $(t,f(t)) = (1,15)$ , then the value of $a$ is: