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zaharov [31]
2 years ago
7

Given quadrilateral QRST - quadrilateral HIJK, QR = 10, QT = 6, and HI = 8, find KH.

Mathematics
2 answers:
Leto [7]2 years ago
5 0

Answer:

B. 24/5

Step-by-step explanation:

Hope this helps

Elis [28]2 years ago
3 0

Answer:

B. 24/5

Step-by-step explanation:

QR = 10

QT = 6

HI = 8

Quadrilateral QRST ~ quadrilateral HIJK, therefore, their corresponding side lengths would be proportional to each other.

This:

QR/HI = QT/HK

Plug in the values

10/8 = 6/HI

Cross multiply

10*HI = 8*6

10*HI = 48

Divide both sides by 10

HI = 48/10

HI = 24/5

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DedPeter [7]

Answer:

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Parent: BT Group, BT Consumer

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Step-by-step explanation:

7 0
2 years ago
Solve for the value of x and y when 3x+2y=24 , x+y=9<br> step wise explanation plz
OLga [1]

Answer:

{x,y} = {2,9}

Step-by-step explanation:

Solve equation [2] for the variable  y  

 

 [2]    2y = -6x + 30

 [2]    y = -3x + 15

// Plug this in for variable  y  in equation [1]

  [1]    3x + 2•(-3x+15) = 24

  [1]    -3x = -6

// Solve equation [1] for the variable  x  

  [1]    3x = 6  

  [1]    x = 2  

// By now we know this much :

   x = 2

   y = -3x+15

// Use the  x  value to solve for  y  

   y = -3(2)+15 = 9

6 0
2 years ago
Read 2 more answers
A soda machine takes 3 seconds to fill a 15-ounce cup. If t represents the time in seconds, which equation can you use to find h
Svet_ta [14]

Information we know:

a 15 ounce cup takes 3 second to fill

determine variables:

x=3

y=15

rate:

y/x=3/15= 0.2

fixture an equation:

y=kx

y=0.2x

plug in 40 for x:

y=0.2(40)

=8

Thus, it should take 8 seconds to fill a 40-ounce cup of soda.

8 0
3 years ago
Read 2 more answers
Let f(x)=cos(arctanx). What is the range of f?
Alenkasestr [34]
-π/2 < arctan(x) < π/2

So cos(π/2) < cos(arctan(x)) < cos(0)

0 < cos(arctan(x)) < 1
4 0
3 years ago
One number is 18 more than another number. The sum of the numbers is 36. find the numbers
tatuchka [14]

We can use a system of equations in order to solve for both of the numbers. Let's start off by assigning variables to each number. The bigger number can be 'x', and the smaller number can be 'y'.

We can make two equations from the given:

x = 18 + y

("One number is 18 more than another number")

x + y = 36

("The sum of the numbers is 36")

If you look at the first equation, the variable 'x' already has a value (18 + y). We can input its value into the second equation in order to solve for y:

x + y = 36

(18 + y) + y = 36

18 + 2y = 36

2y = 18

y = 9

Input the value of 'y' into the first equation:

x = 18 + y

x = 18 + 9

x = 27

<u>One number is 27 and the other number number is 9.</u>

<u></u>

Let me know if you'd like me to explain anything I did here.

- breezyツ

7 0
3 years ago
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