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4 years ago

/Algebra/Can someone please help.

Mathematics

1 answer:

Mrac [35]4 years ago

3 0

Answer:

The answer is A

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Jake says he can run of a mile in of an hour. How fast is this in miles per hour?

UNO [17]

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3 years ago

Alex usually runs for 21 hours a week training for a marathon if he is unable to run for three days describe how to find out how

Igoryamba

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3 years ago

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Graphing sucks

bulgar [2K]

- you can substitue x and y for 1, or 0 and graph each point

- use desmos and copy it

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3 years ago

The Greater Pittsburgh Area Chamber of Commerce wants to estimate the mean time workers who are employed in the downtown area sp

Valentin [98]

Answer:

98% Confidence interval: (31.74,38.4)

Step-by-step explanation:

We are given the following data set:

29, 38, 38, 33, 38, 21, 45, 34, 40, 37, 37, 42, 30, 29, 35

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{526}{15} = 35.07$

Sum of squares of differences = 506.93

$S.D = \sqrt{\displaystyle\frac{506.93}{14}} = 6.02$

98% Confidence interval:

$\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 14 and}~\alpha_{0.02} = \pm 2.145$

$35.07 \pm 2.145(\frac{6.02}{\sqrt{15}} ) = 35.07 \pm 3.33 = (31.74,38.4)$

Thus, there is 98% confidence that the population mean number of minutes spent traveling by workers is between 31.74 mins and 38.40

4 0

3 years ago

May someone please help mee????

Arlecino [84]

Answer:

width of rectangle is 87

Step-by-step explanation:

because perimeter of rectangle = 2(l+w)

3 0

3 years ago

/Algebra/Can someone please help.​

/Algebra/Can someone please help.