Actually there are three types of construction that were never accomplished by Greeks using compass and straightedge these are squaring a circle, doubling a cube and trisecting any angle.
The problem of squaring a circle takes on unlike meanings reliant on how one approaches the solution. Beginning with Greeks Many geometric approaches were devised, however none of these methods accomplished the task at hand by means of the plane methods requiring only straightedge and a compass.
The origin of the problem of doubling a cube also referred as duplicating a cube is not certain. Two stories have come down from the Greeks regarding the roots of this problem. The first is that the oracle at Delos ordered that the altar in the temple be doubled over in order to save the Delians from a plague the other one relates that king Minos ordered that a tomb be erected for his son Glaucus.
The structure of regular polygons and the structure of regular solids was a traditional problem in Greek geometry. Cutting an angle into identical thirds or trisection was another matter overall. This was necessary to concept other regular polygons. Hence, trisection of an angle became an significant problem in Greek geometry.
The diagram shows that FG = IJ are congruent segments due to the double tickmarks. These are the hypotenuses of the right triangles.
So that takes care of the "H" in "HL".
The L stands for "leg", so we need to have a congruent pair of corresponding legs.
Due to the orientation of the triangles, it's not clear how the corresponding legs match up, but if any of the following is true
- EF = IK
- EF = JK
- EG = IK
- EG = JK
then we'd have enough to use HL.
Answer:
Both flights approach each other at a speed of 624.70 Knots. The FAA minimum separation is not violated as both airplanes are 7.26 Nautical miles away from each other at the time when one of the flights( flight AA) passes through Frada Heights.
Step-by-step explanation:
To solve this kind of problem, the knowledge of concept of relative velocity is needed as the first question requested how fast the flights were approaching each other. To find the minimum distance between both flights, the closest point of approach between both flights should be taken into consideration which was Frada heights. Flight AA passes through Frada Heights in a shorter time of 0.079 hours. This is the time at which both flights approach each other the closest and so the minimum distance (separation) between them. This was calculated to be 7.26NM which is greater than the FAA's minimum this requirement for flight was not violated.
Detailed calculation steps can be found in the attachment below.
Probability is what the letter p indicates
Answer:nhnc
add it mc
Step-by-step explanation:vgnhc
