Question

Probability theory predicts that there is a 70% chance of a particular soccer player making two penalty shots in a row. If the soccer player taking two penalty shots is simulated 2500 times in about how many of the simulations would you expect at least one missed shot

Answer 1

The probability of the player missing a shot at least once is 1.00 - 0.70 = 0.3.
Therefore the average number of missed double goals in 2500 trials is given by:
$2500\times0.3=750$