Answer:
Value of p is 3
Step-by-step explanation:
One of the root is 1.
So, putting 1 in the place of x in the given equation,
px²-4x+3p-8=0
or, p-4+3p-8=0
or, 4p-12=0
or, 4p=12
or, p=3
Answered by GAUTHMATH
Answer:
a. 2n = 3n − 12, 12
Step-by-step explanation:
Let the number be represented by n.
Then 2 times the number is 2*n = 2n
3 times the number = 3*n = 3n
12 minus 3 times the number is 3n-12
It is given that 2 times the number is the same as 12 minus 3 times the number.
Expressing this equation form:
![\[2n=3n-12\]](https://tex.z-dn.net/?f=%5C%5B2n%3D3n-12%5C%5D)
Solving the equation,
![\[3n-2n=12\]](https://tex.z-dn.net/?f=%5C%5B3n-2n%3D12%5C%5D)
![\[=> n=12\]](https://tex.z-dn.net/?f=%5C%5B%3D%3E%20n%3D12%5C%5D)
Hence the required number is 12.
5 is correct! the real answer is 4.80
Answer:
y=2e^(−x)cosx−e^(−x)sinx
Satisfies the equation
Step-by-step explanation:
Answer:
y=2e^(−x)cosx−e^(−x)sinx
y = e^(-x)[2cosx - sinx]
Find y' and y" using product law
y' = -e^(-x)[2cosx - sinx] + e^(-x)[-2sinx - cosx]
y' = -e^(-x)[2cosx - sinx + 2sinx + cosx]
y' = -e^(-x)[3cosx + sinx]
y" = e^(-x)[3cosx + sinx] - e^(-x)[-3sinx + cosx]
y" = e^(-x)[3cosx - cosx + sinx + 3sinx]
y" = e^(-x)[2cosx + 4sinx]
y" + 2y' + 2y
e^(-x)[2cosx + 4sinx] - 2e^(-x)[3cosx + sinx] +2e^(-x)[2cosx - sinx]
e^(-x)[4sinx - 2sinx - 2sinx + 2cosx - 6 cosx + 4cosx]
= e^(-x) × 0
= 0
Answer:
The function has 2 zeros:

Step-by-step explanation:
When you have a polynomial function, you can identify the grade of the function (the grade is the maximum potency) and this is the number of zeros that the function will have. In this case, you have a second-grade polynomial function that has 2 zeros.