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katen-ka-za [31]
3 years ago
9

Is the square root of eight a rational or irrational number

Mathematics
1 answer:
shutvik [7]3 years ago
8 0
\bf \sqrt{8}\implies \sqrt{2\cdot 2\cdot 2}\implies \sqrt{2^2\cdot 2}\implies 2\sqrt{2}

it just so happen that √2 is an irrational number, so any product with it as a factor, will yield an irrational number as well.



factoid:   Ancient Greeks were scared of irrational numbers, and they steered clear from √2.
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Consider the equation 5x (2x + 1) - 3(2x + 1) = 0.
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Answer:

It is equivalent to 15x – 3)(2x + 1) = 0.       False

It is equivalent to (5x – 3)(2x + 1) = 0        True

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Step-by-step explanation:

Consider the equation 5x (2x + 1) - 3(2x + 1) = 0.

It is equivalent to 15x – 3)(2x + 1) = 0.       False

It is equivalent to (5x – 3)(2x + 1) = 0        True

When you take pull-out (2x+1), you will be left with (5x-3)

5x (2x + 1) - 3(2x + 1) = 0.

(2x+1)(5x-3)=0

Either 2x + 1 = 0                        

2x = -1    

Divide both-side of the equation by 2

2x/2 = -1/2                                    

  x= -1/2                                        

OR

5x-3 =0

5x = 3

Divide both-side of the equation by 5

5x/5 = 3/5

x = 5/3

Either   x=-1/2   or    5/3

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