Question

A bag has 4 red 3 white 2 blue and 1 green marble in it. Use this information to answer question 9-11.

Answer 1

Answer:

Step-by-step explanation:

r=4, w=3, b=2, g=1, t=(4+3+2+1)=10

9) P(r or g)=4/10+1/10=5/10= 1/2

10) P(r or b)=4/10+2/10=6/10= 3/5

11) P(!b)=P(r or w or g)=4/10+3/10+1/10=8/10= 4/5

12) There are six numbers and only one six, P(6)= 1/6

13) The only even numbers less than 5 are 2 and four so

P(e<5)=2/6= 1/3

14) The primes on a die are 2,3,5 so three primes out of six numbers

P(!)=3/6= 1/2

15) 2,3,4,6 are multiples of 2 and three

P(2n or 3n)=4/6= 2/3

16) We want a one half probability so

P(W)=(3+x)/(3+4+2+x)=1/2

(3+x)/(9+x)=1/2

2(3+x)=9+x

6+2x=9+x

x=3

So 3 white marbles have to be added.

17) (3+x)/(9+x)=2/3

3(3+x)=2(9+x)

9+3x=18+2x

x=9

So nine whites need to be added.

Answer 2

#'s 9-14

Base info:   40% are red, 30% are white, 20% are blue, and 10% are green

9) 40% chance to get red, 10% chance to get green. 50% chance to get one of either.

10) getting red: 40%

Getting blue: 20%

11) 80%  (100% - 20% = 80%)

1/8 = 12.5%

12) 12.5% chance

13) 25% chance

14) 12.5 x 5 = 62.5  

62.5% chance