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12345 [234]
4 years ago
14

Solve the following system of equations:3x − 2y = 66x − 4y = 12

Mathematics
1 answer:
xz_007 [3.2K]4 years ago
8 0
3x - 2y = 66
x - 4y = 12....multiply by -3
---------------
3x - 2y = 66
-3x + 12y = - 36 (result of multiplying by -3)
---------------add
10y = 30
y = 30/10
y = 3

3x - 2y = 66
3x  - 2(3) = 66
3x - 6 = 66
3x = 66 + 6
3x = 72
x = 72/3
x = 24

solution is : (24,3)
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AB with coordinates A(6, –4), B(11, –4)  is given as:

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BC with coordinates B(11, –4), C(11, 6)  is given as:

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CD with coordinates C(11, 6), D(6, 6)  is given as:

CD = \sqrt{(11-6)^2 + (6-6)^2} =  \sqrt{(5)^2 + 0} = 5

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AD with coordinates A(6, –4),D(6, 6)  is given as:

AD = \sqrt{(6-6)^2 + (-4-(-4))^2} =  \sqrt{(0)^2 + 10^2} = 10

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