Answer:
We can get 27 pieces of wire 3.6 cm long and have a piece 7/9 cm left over
Step-by-step explanation:
Find the "unit length" by dividing 1 m by 3.6 cm:
1 m
-----------
3.6 cm
Recall that 1 m = 100 cm. Multiply the following by the conversion factor 100 cm / 1 m:
1 m 100 cm
----------- * ----------------- = 27,7777777...
3.6 cm 1 m
We can get 27 pieces of wire 3.6 cm long and have a piece 7/9 cm left over (verify this by dividing 7 by 9 on a calculator).
Equation 1.
20÷4=5
0×3=0
5-5=0
Equation 2.
44÷4=11
2×3=6
11-5=6
Equation 3.
56÷4=14
3×3=9
14-5=9
Answer:
Not true
Step-by-step explanation:
x + (2x + 5) = 3(x – 4)+7
Opening bracket on left and side and distributing 3 over (x-4) on right hand side
x+2x+5=3x-3 x 4 + 7
adding like terms
3x+5=3x-12+7
3x+5=3x-5
Hence
5 = -5
Which is not possible , Hence the equation given to us is false.
16 thru 23 look wrong and 16 is absolutely wrong. You use this:https://www.mathpapa.com/algebra-calculator.html to work out the answers and it shows the steps and explains it to you better than I could. Good luck
