We reject our null hypothesis, H₀, at a level of significance of =0.01 since the P-value is less than that threshold. There is compelling statistical data to indicate that since 1991, the proportion of drivers who love driving has decreased.
Given,
The Pew Research Center recently polled n=1048 U.S. drivers and found that 69% enjoyed driving their automobiles.
In 1991, a Gallup poll reported this percentage to be 79%. using the data from this poll, test the claim that the percentage of drivers who enjoy driving their cars has declined since 1991.
To report the large-sample z statistic and its p-value,
Null hypothesis,
H₀ : p = 0.79
Alternative hypothesis,
Ha : p < 0.79
Level of significance, α = 0.01
Under H₀
Test statistic,

Z₀ = -7.948
The alternative hypothesis(Ha) is left-tailed, so the P-value of the test is given by
P-value = P(z <-7.945)
= 0.000 (from z-table)
Since the P-value is smaller than given level of significance, α=0.01 we reject our null hypothesis, H₀, at α=0.0.1 level Strong statistical evidence to conclude that the percentage of drivers who enjoy driving their cars has declined since 1991.
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It is 75000J
I checked this by plugging in the values above to the kinetic energy formula (1/2mv^2)
Just a guess but I think it is 0.43. By dividing the decimal 0.02 into the Denominator
Step-by-step explanation:
ABC+DAB=180
DAB=180-115
DAB= 65
m<3+m<4=65
m<3=65-m<4
You have been given 4 degrees there, but it has not fallen. The answer is either A or B. Subtracting the conditional degree from 65. Find 3.
The formula for percentage is:
is/of = %/100
In the given problem,
is = ?
of = 25
% = 80
We get,
?/25 = 80/100
"is" is unknown so let "is" be "x"
x/25 = 80/100
We have to cross multiply. Meaning, we will multiply the numerator of one fraction by the denominator of the other fraction. Therefore,
100x = (80)(25)
100x = 2000
x = 20
The answer is 20. The basketball player is expected to make 20 free throw shots out of 25 in the entire game.