Question

Please help me on this

Answer 1

For this case we have to define root properties:

$\sqrt [n] {a ^ n} = a ^ {\frac {n} {n}} = a$

In addition, we know that:

$a ^ {- 1} = \frac {1} {a ^ 1} = \frac {1} {a}$

On the other hand:

$4 ^ 2 = 16$

Thus, we can rewrite the given expression as:

$\sqrt {4 ^ 2 * a ^ 8 * \frac {1} {b ^ 2}} =\\4 ^ {\frac {2} {2}} * a ^ {\frac {8} {2}} * \frac {1} {b ^ {\frac {2} {2}}} =\\4 * a ^ 4 * \frac {1} {b}$

ANswer:

Option B