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siniylev [52]
3 years ago
9

You want to find out how sleep deprivation affects motor performance. To study this, you have sleep-deprived subjects (such as p

arents of newborn babies or night-shift workers) record the number of minutes they sleep each night and take a series of motor performance assessments, with 1 minute being the smallest unit on the scale. Suppose the first subject sleeps 180 minutes. Determine the real limits of 180.
Mathematics
1 answer:
marysya [2.9K]3 years ago
7 0

Answer:

179.5 - 180.5

Step-by-step explanation:

Time is a continuous variable. The minimum sleep time per night per subject here, is given as 1 minute.

Larger sleep times could be 1.08 minutes, 2.99 minutes, and other continuous/infinite values. Remember there are 60seconds in a minute and in-between seconds, there are milliseconds. So time is a continuous variable.

In this case though, our measurement of time is given in whole number units (integers). Our precision of measurement is 1 unit. We have an observed value of 180 minutes (the first subject's sleep time). The real limits of this value are 179.5 to 180.5

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Caleb is putting tile down in his bathroom and needs to know the perimeter of the floor. Two sides rectangular floor are 5 1/3 f
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Answer:

  20 1/6 ft

Step-by-step explanation:

The perimeter is the sum of the lengths of the sides:

  2×(5 1/3 ft) + 2×(4 3/4 ft) = 10 2/3 ft + 8 6/4 ft

  = 10 2/3 ft + 9 2/4 ft . . . . change 6/4 ft to 1 1/2 ft

  = 10 8/12 ft + 9 6/12 ft = 19 14/12 ft  . . . . . use common denominator of 1/12 ft

  = 20 2/12 ft . . . . . . change 14/12 ft to 1 2/12 ft; next reduce that fraction

  = 20 1/6 ft . . . . perimeter of Caleb's bathroom

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san4es73 [151]
Your answer would be B.
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levacccp [35]
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Explanation:
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