Answer:
Step-by-step explanation:
To preface, your figure is going to be a line segment, with 
as your midpoint, in between points 
& 
With that being said:
Identify your values:
Substitute the values into the first equation:
Combine like terms:
Subtract 
from both sides of the equation:
Divide by the coefficient of 
, which is 
:
Substitute 
for in segments 
& 
:
Solve:
Check your answers by substituting:
Answer:
please pay attention during your classes.
Step-by-step explanation:
Answer:
Step-by-step explanation:
<h3>Given</h3>
- h(x) = (f ο g)(x)
- h(x) =
- f(x) =
<h3>To find</h3>
<h3>Solution</h3>
<u>We know that:</u>
<u>Substitute x with g(x) and solve for g(x):</u>
- =
- x + 5 = g(x) + 2
- x + 3 = g(x)
- g(x) = x + 3
I'm guessing it is 10? or 7?
Answer: 
Step-by-step explanation:
Given
Julien's parents want $64,000 at the end of 3 years
The rate of interest is 10% annually
Suppose they invested P amount initially
So, compound interest, compounded monthly is
![\Rightarrow A=P\left( 1+\frac{r}{n}\right)^{nt}\quad [\text{n=Numner of compounding periods}]\\\\\text{Insert the values}\\\Rightarrow 64,000=P\left( 1+\frac{0.10}{12}\right)^{12\times 3}\\\\\Rightarrow 64,000=P\left( 1+\frac{10}{12}\right)^{36}\\\\\Rightarrow P=\dfrac{64000}{1.3481}\\\\\Rightarrow P=\$\ 47,471.37\approx \$ 47,471](https://tex.z-dn.net/?f=%5CRightarrow%20A%3DP%5Cleft%28%201%2B%5Cfrac%7Br%7D%7Bn%7D%5Cright%29%5E%7Bnt%7D%5Cquad%20%5B%5Ctext%7Bn%3DNumner%20of%20compounding%20periods%7D%5D%5C%5C%5C%5C%5Ctext%7BInsert%20the%20values%7D%5C%5C%5CRightarrow%2064%2C000%3DP%5Cleft%28%201%2B%5Cfrac%7B0.10%7D%7B12%7D%5Cright%29%5E%7B12%5Ctimes%203%7D%5C%5C%5C%5C%5CRightarrow%2064%2C000%3DP%5Cleft%28%201%2B%5Cfrac%7B10%7D%7B12%7D%5Cright%29%5E%7B36%7D%5C%5C%5C%5C%5CRightarrow%20P%3D%5Cdfrac%7B64000%7D%7B1.3481%7D%5C%5C%5C%5C%5CRightarrow%20P%3D%5C%24%5C%2047%2C471.37%5Capprox%20%5C%24%2047%2C471)
