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3 years ago

PLEASE HELLLLLLP!!!!!!!

2 answers:

6 0

1. B. (c-8)(c+8)
2. C. 3(2y-5)(2y+5)
3. D. 9(y-2)(y+2)
4. C. -(x-1)(x-4)
5. D. b(ab-1)

i hope this helps u out!

AVprozaik [17]3 years ago

3 0

The answers for this practice are as follows:

1. B) (x+2)(x+5)

2. C) (x-2)(x-1)

3. D) -(x+5)(x-8)

4. A) 3

5. D) 5b

6. B) (c-8)(c+8)

7. C) 3(2y-5)(2y+5)

8. D) 9(y-2)(y+2)

9. C) -(x-1)(x-4)

10. D) b(ab-1)

Just took the quiz and got all of them right

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On Sunday, a local hamburger shop sold a combined total of 428 hamburgers and cheeseburgers. The number of cheese burgers sold w

melisa1 [442]

The equation you can use is x + 3x = 428 with x as the number of cheeseburgers and 3x the number of hamburgers
you solve for x and get 4x= 428 and x=107

so 321 hamburgers were sold that day.

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2 years ago

A man is standing on top of a 400 ft. tall building. He sees two people approaching the building along a straight road. He sees

Marina CMI [18]

Answer:

Draw a diagram. Then use tan(x) to find the remainder height of the taller building.

Step-by-step explanation:

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2 years ago

Help me find the volume of the composite figure

Butoxors [25]

Answer:

$V = 97.911in^3$

Step-by-step explanation:

Given

Shapes: Cube and Cone

Required

Determine the volume

First we calculate the volume of the cube

$V_1 = l^3$

Where

l = side length = 5.1

$V_1 = 5.1^3$

$V_1 = 132.651$

Next, calculate the volume of the cone using:

$V_2 = \frac{\pi r^2h}{3}$

Where

h = 5.1

$r = \frac{1}{2} * Diameter$

$r = \frac{1}{2} * 5.1$

$r = 2.55$

So, we have:

$V_2 = \frac{\pi r^2h}{3}$

$V_2 = \frac{\pi * 2.55^2 * 5.1}{3}$

$V_2 = \frac{22 * 2.55^2 * 5.1}{7*3}$

$V_2 = \frac{729.5805}{21}$

$V_2 = 34.74$

The volume of the figure is:

$V=V_1 - V_2$

$V_1 = 132.651$

$V = 132.651 - 34.74$

$V = 97.911in^3$

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2 years ago

Assuming that the equations define x and y implicitly as differentiable functions x=f(t),y=g(t) find the slope of the curve x=f(

Mumz [18]

The given equations are
$x(t+1)-4t \sqrt{x} =9$ (1)
$2y+4y^{3/2}=t^{3}+t$ (2)

When t=0, obtain
$x=9 \\ 2y+4y^{3/2}=0 \,\,=\ \textgreater \ \, y(1+2 \sqrt{y} )=0 \,=\ \textgreater \ \,y=0$

Obtain derivatives of (1) and find x'(0).
x' (t+1) + x - 4√x - 4t*[(1/2)*1/√x = 0
x' (t+1) + x - 4√x -27/√x = 0
When t=0, obtain
x'(0) + x(0) - 4√x(0) = 0
x'(0) + 9 - 4*3 = 0
x'(0) = 3
Here, x' means $\frac{dx}{dt}$ .

Obtain the derivative of (2) and find y'(0).
2y' + 4*(3/2)*(√y)*(y') = 3t² + 1
When t=0, obtain
2y'(0) +6√y(0) * y'(0) = 1
2y'(0) = 1
y'(0) = 1/2.
Here, y' means $\frac{dy}{dt}$ .

Because $\frac{dy}{dx} = \frac{dy}{dt} / \frac{dx}{dt}$ , obtain
$\frac{dy}{dx} |_{t=0}\, = \frac{1/2}{3}= \frac{1}{6}$

Answer:
The slope of the curve at t=0 is 1/6.

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2 years ago

3. Bob the Builder wants to earn an annual rate of 10% on his investments,

mamaluj [8]

Answer:

He should pay $2,790.7.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

$E = P*I*t$

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time, in years.

After t years, the total amount of money is:

$T = E + P$