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3 years ago

5

A store has two different brands of laundry detergent. Brand A can do 80 loads of laundry and costs $12.75. Brand B does 36 load

s of laundry and costs $6.75. Which laundry detergent costs less per load?

2 answers:

strojnjashka [21]3 years ago

7 0

Brand a is around 16 cents per load while brand b is around 19 cents per load so brand a cost lest

kap26 [50]3 years ago

4 0

Brand a costs less per load because b is more expensive per load

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1/4 (-12+3) -8/3<br> Simplified

labwork [276]

Answer:

-59/12

Step-by-step explanation:

finish whats inSide brackets first

so -12+3 =-9

-9*1/4 will be next and = -9/4

9/4+8/3 =. 59 /12

6 0

2 years ago

A curious patterns occurs in a group of people who all shake hands with one another. It turns out that you can predict the numbe

ycow [4]

Missing part of the question

Determine the number of handshakes, i, that will occur for each number of people, n, in a particular room. (people)

Answer:

$S_n = \frac{n}{2}(n - 1)$

Step-by-step explanation:

Given

For 5 people

$\begin{array}{cc}{People} & {Handshakes} & {5} & {4} & {4} & {3} & {3} & {2} & {2} & {1} & {1} & {0} &{Total} & {10} \ \end{array}$

Using the given instance of 5 people, the number of handshakes can be represented as:

$(n - 1) + (n - 2) + (n - 3) + ........ + 3 + 2 + 1 + 0$

The above sequence is an arithmetic sequence and the total number of handshakes is the sum of n terms of the sequence.

$S_n = \frac{n}{2}{(T_1 + T_n})$

Where

$T_1 = n - 1$ --- The first term

$T_n = 0$ --- The last term

So:

$S_n = \frac{n}{2}(n - 1 + 0)$

$S_n = \frac{n}{2}(n - 1)$

7 0

2 years ago

WILL GIVE 100 POINTS AND BRAINLIEST FOR BEST ANSWER

coldgirl [10]

Answer:

Step-by-step explanation:-16x^2 + 24x + 16 = 0.

A. Divide by 8:

-2x^2 + 3x + 2 = 0, A*C = -2*2 = -4 = -1 * 4. Sum = -1 + 4 = 3 = B, -2x^2 + (-x+4x) + 2 = 0,

(-2x^2-x) + (4x+2) = 0,

-x(2x+1) + 2(2x+1) = 0,

(2x+1)(-x+2) = 0, 2x+1 = 0, X = -1/2. -x+2 = 0, X = 2.

X-intercepts: (-1/2,0), (2,0).

B. Since the coefficient of x^2 is negative, the parabola opens downward. Therefore, the vertex is a maximum.

Locate the vertex: h = Xv = -B/2A = -24/-32 = 3/4, Plug 3/4 into the given Eq to find k(Yv). K = -16(3/4)^2 + 16(3/4) + 16 = 19. V(h,k) = V(3/4,19).

C. Choose 3 points above and below the vertex for graphing. Include the points calculated in part A which shows where the graph crosses the x-axis.

4 0

3 years ago

Three students, Matthew, Thompson and Amos shared #15000 in the ratio of 5:2:x respectively. If Matthew's share is 7500, calcula

jasenka [17]

Answer:

The value of x is 3.

Step-by-step explanation:

Matthew earned 7500 of 15000, which is exactly half the total amount, meaning that the fraction corresponding to his earnings is 1/2.

Rate of 5:2:x, with number 5 corresponding to Matthew, mean that his fraction of the earnings, in function of x is given by:

$\frac{5}{5 + 2 + x} = \frac{5}{7 + x}$

Both fractions are equal, so:

$\frac{5}{7 + x} = \frac{1}{2}$

Applying cross multiplication:

$7 + x = 10$

$x = 10 - 7$

$x = 3$

The value of x is 3.

5 0

2 years ago

If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)

sweet-ann [11.9K]

Answer:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

Step-by-step explanation:

Given

$tan\theta = 3$

Required

Find

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$

Calculate $tan(\theta + \pi) \ and\ tan(\theta+2\pi)$

Using tan rule

$tan(\theta + \pi) = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}$

So:

$tan(\theta + \pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + \pi) = \frac{tan\theta}{1 }$

$tan(\theta + \pi) = \tan\theta$

$tan(\theta+2\pi)$

$tan(\theta + 2\pi) = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}$

$tan(\theta + 2\pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + 2\pi) = \tan\theta$ '

'So:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$ $= tan\theta +tan\theta +tan\theta$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

4 0

2 years ago