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3 years ago

5

snail travels at a rate of 2.37 feet per minute. write a route to describe the function how far will the snail travel in six min

utes

1 answer:

Alex3 years ago

5 0

F(x)=2.37ft*(X)
if x=6
then you multiply the amount of feet per minute which is 2.37 by 6
2.37*6=14.22
so your answer would be 14.22

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A company must select 4 candidates to interview from a list of 12, which consist of 8 men and 4 women.

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Part A

If 4 candidates were to be selected regardless of gender, that means that 4 candidates is to be selected from 12.

The number of possible selections of 4 candidates from 12 is given by

$^{12}C_4= \frac{12!}{4!(12-4)!}= \frac{12!}{4!\times8!} =11\times5\times9=495$

Therefore, the number of <span>selections of 4 candidates regardless of gender is 495.

Part B:

</span>
<span>If 4 candidates were to be selected such that 2 women must be selected, that means that 2 men candidates is to be selected from 8 and 2 women candidates is to be selected from 4.

The number of possible selections of </span><span>2 men candidates from 8 and 2 women candidates from 4 is given by

</span><span> $^{8}C_2\times ^{4}C_2= \frac{8!}{2!(8-2)!}\times 
\frac{4!}{2!(4-2)!} \\ \\ = 
\frac{8!}{2!\times6!}\times\frac{4!}{2!\times2!} 
=4\times7\times2\times3=168$

Therefore, the number of selections of 4 candidates </span><span>such that 2 women must be selected is 168.</span>

Part 3:

If 4 candidates were to be selected such that at least 2 women must be selected, that means that 2 men candidates is to be selected from 8 and 2 women candidates is to be selected from 4 or 1 man candidates is to be selected from 8 and 3 women candidates is to be selected from 4 of <span>no man candidates is to be selected from 8 and 4 women candidates is to be selected from 4.

The number of possible selections of </span>2 men candidates from 8 and 2 women candidates from 4 of <span>1 man candidates from 8 and 3 women candidates from 4 of no man candidates from 8 and 4 women candidates from 4 is given by
</span><span>
$^{8}C_2\times ^{4}C_2+ ^{8}C_1\times ^{4}C_3+ ^{8}C_0\times ^{4}C_4 \\ \\ = \frac{8!}{2!(8-2)!}\times \frac{4!}{2!(4-2)!}+\frac{8!}{1!(8-1)!}\times \frac{4!}{3!(4-3)!}+\frac{8!}{0!(8-0)!}\times \frac{4!}{4!(4-4)!} \\ \\ = \frac{8!}{2!\times6!}\times\frac{4!}{2!\times2!}+\frac{8!}{1!\times7!}\times\frac{4!}{3!\times1!}+\frac{8!}{0!\times8!}\times\frac{4!}{4!\times0!} \\ \\ =4\times7\times2\times3+8\times4+1\times1=168+32+1=201$

Therefore, the number of selections of 4 candidates </span><span>such that at least 2 women must be selected is 201.</span>

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Flauer [41]

1.x=1 y=5

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Which equation defines the graph of y=x^2 after it is shifted vertically 3 units down and horizontally 5 units left? A) y=(x-5)^

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Pencils come in packages of 10.Erasers come in packages of 12. Phillips wants to purpose the smallest number of pencils and eras

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Answer:

The answer to your question is:

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Step-by-step explanation:

Data

Pencils = 10/package

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Find the least common factor of 10 and 12

10 12 2

5 6 2

5 3 3

5 1 5

1

LCF = 2 x 2 x 3 x 5 = 60

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