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Serga [27]
3 years ago
8

Mario and 3 friends each had 3/4 foot of rope. They needed 5 feet of rope altogether. Do they have enough? Explain.     

Mathematics
1 answer:
dangina [55]3 years ago
6 0
They would not have enough because 3/4  times 4  would not equal 5...it would equal 3. Mario and his 3 friends each have 3/4 foot of rope. They needed 5 feet of rope altogether. Do they have enough rope? They would need 2 more feet of rope to complete the 5 feet. But they do not have enough feet of rope to make 5 feet. 

hope this helps :D
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Samara was playing a game. She wrote down this number sentence to find the total number of points for 11 games in a row.
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3 years ago
Solve for m. (-11/6) + m = -2/9
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Answer:

m = \frac{29}{18}

Step-by-step explanation:

=> (-11/6) + m = -2/9

Adding 11/6 to both sides

=> m = -\frac{2}{9} + \frac{11}{6}

LCM = 18

=> m = \frac{-4+33}{18}

=> m = \frac{29}{18}

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If (-2,4) are the coordinates of a point on the line whose equation is y=Mx+1 , what is the slope of the line?
horrorfan [7]

Slope of the line is -3/2

Step-by-step explanation:

  • Step 1: Given that (-2, 4) is a point on the line y = mx + 1, find slope m.

Since the point is on the line, the coordinates will satisfy the equation.

⇒ 4 = m × -2 + 1

⇒ 4 = -2m + 1

⇒ 3 = -2m

∴ m = -3/2

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3 years ago
Suppose that the mean retail price per gallon of regular grade gasoline in the United States is $3.47 with a standard deviation
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Step-by-step explanation:

Your answer

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8 0
3 years ago
Use the arc length formula to find the length of the curve y = 2 − x2 , 0 ≤ x ≤ 1. Check your answer by noting that the curve is
Lina20 [59]

By using the arc length formula, we will see that the length of the curve is L = 1.48

<h3>How to use the arc length formula?</h3>

Here we have the curve:

y = 2 - x^2   with 0 ≤ x ≤ 1

And we want to find the length of the curve.

The arc length formula for a curve y in the interval [x₁, x₂] is given by:

L  =\int\limits^{x_2}_{x_1} {\sqrt{1 + \frac{dy}{dx}^2} } } \, dx

For our curve, we have:

dy/dx = -2x

And the interval is [0, 1]

Replacing that we get:

L  =\int\limits^{1}_{0} {\sqrt{1 + (-2x)^2} } } \, dx\\\\L  \int\limits^{1}_{0} {\sqrt{1 + 4x^2} } } \, dx\\

This integral is not trivial, using a table you can see that this is equal to:

L = (\frac{Arsinh(2x)}{4}  + \frac{x*\sqrt{4x^2 + 1} }{2})

evaluated from x = 1 to x = 0, when we do that, we will get:

L = \frac{Arsinh(2) + 2*\sqrt{5} }{4}  = 1.48

That is the length of the curve.

If you want to learn more about curve length, you can read:

brainly.com/question/2005046

8 0
2 years ago
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