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nadezda [96]
3 years ago
13

0.3d - 12 = 0.6 what’s the value of d?

Mathematics
2 answers:
rjkz [21]3 years ago
8 0

Step 1: seclude "D"

0.3d=0.6+12

Step 2: Divide both sides by 0.3

D=0.6/0.3 + 12/0.3

D= 2+40

D=42

Solved

Wittaler [7]3 years ago
3 0

Answer:

d= 42

Step-by-step explanation:


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pav-90 [236]

Answer:

AB=7.21 unit

BC=6 unit

CD=7.21 unit

AD= 6 unit

AC=4 unit

BD=4 unit

Step-by-step explanation:

Coordinates of A =(-2,3)

Coordinates of B = (2,-3)

Coordinates of C = (2,3)

Coordinates of D =(-2,-3)

Distance formula :d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

A=(x_1,y_1)=(-2,3)\\B=(x_2,y_2)=(2,-3)\\AB = \sqrt{(2+2)^2+(-3-3)^2}

AB=7.21 unit

B=(x_1,y_1)=(2,-3)\\C=(x_2,y_2)=(2,3)\\BC=\sqrt{(2-2)^2+(3+3)^2}

BC=6

C=(x_1,y_1)=(2,3)\\D=(x_2,y_2)=(-2,-3)\\CD=\sqrt{(-2-2)^2+(-3-3)^2}

CD=7.21

A=(x_1,y_1)=(-2,3)\\D=(x_2,y_2)=(-2,-3)\\AD=\sqrt{(-2+2)^2+(-3-3)^2}

AD=6

A=(x_1,y_1)=(-2,3)\\C=(x_2,y_2)=(2,3)

AC=\sqrt{(2+2)^2+(3-3)^2}

AC=4

B=(x_1,y_1)=(2,-3)\\D=(x_2,y_2)=(-2,-3)

BD=\sqrt{(-2-2)^2+(-3+3)^2}

BD=4

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3 years ago
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Answer:

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The position of an open-water swimmer is shown in the graph. The shortest route to the shoreline is one that is perpendicular to
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Answer:

Step-by-step explanation:

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m=-2

For lines to be perpendicular their slopes must satisfy

m1m2=-1, we have a line with a slope of -2 so

-2m=-1

m=1/2, so our perpendicular line is so far

y=x/2+b, it must have point (3,2) so we can solve for b

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b=1/2, so the swimmer will travel along the line

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Answer:

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