I hope this helps you
x=4 q (4)=8.4-7
q (4)=32-7
q (4)=25
If you are asking if your work is good,thn yes,you are right
Answer:
g(-1 )=-1 and g(2)+g(1)=7
Step-by-step explanation:
If g(x) = x^3+x^2-x-2 find g(-1)
if we find g(-1)
we substitute all the x's in the function with -1
-1^3+-1^2-(-1)-2
-1^3 = -1
-1^2 = 1
-1+1+1-2
(two minuses make a plus)
-1+1 = 0
0+1 = 1
1-2 = -1
if x=-1, g(-1) is -1
g(2)+g(1)
substitute the x's in the function with 2 and 1 and add your results
2^3+2^2-2-2
2^3 = 8, 2^2 = 4
8+4-2-2
8+4= 12, 12-2 = 10, 10-2 = 8
g(2)=8
g(1) now
1^3 + 1^2-1-2
1^3=1, 1^2 = 1
1+1-1-2
1+1 = 2, 2-1 = 1, 1-2 = -1
g(3) = -1
g(2) (which equals 8) + g(3) (which equals -1) =
8+(-1) = 7
g(2)+g(3)=7
Answer: $6.48
Step-by-step explanation:
1.60 * 0.1 = $0.16
1.60 - 0.16 = $1.44
1.44 * 4.5 = $6.48
The base is from 2 to 7, which is 5 units long.
The height is from 1 to 8, which is 7 units tall.
Using the Pythagorean theorem we can calculate the hypotenuse:
Hypotenuse = √5^2 +7^2=
√25 +49=
√74=
8.6
Perimeter = 5 + 7 + 8.6 = 20.6
The answer is C.
