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3 years ago

If line VX is the bisector of angle V, find the perimeter of triangle VUW .

Mathematics

1 answer:

umka21 [38]3 years ago

6 0

Since VX is the bisector of angle V and < VXU is a right angle then UX is congruent to XW and triangle VUW is isosceles with VU = VW.

3z - 4 = x + 6
2z = 10
z = 5

so UW = 3(5) - 4 + 5 + 6 = 22
and VW = 5(5) - 1 = 24

VU = VW = 24

perimeter = 2(24) + 22 = 70

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ELEN [110]

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3 years ago

If you buy tomato sauce for $.90 a quart how much does it cost for 5 pints

Dima020 [189]

<h2>Hello!</h2>

The answer is: the price of 5 pints of tomato sauce is $2.25.

To calculate how much does it cost 5 pints, we need to perform a unit conversion with the following unit relationship:

$0.5Quart=Pints$

Now, calculating how much is a pint:

$\frac{0.9}{quarter}*\frac{0.5Quart}{1Pint}=0.45$

A pint is $0.45.

Then, calculating how much are 5 pints:

$Price=0.45*NoOfPints=0.45*5=2.25$

Hence, the price of 5 pints of tomato sauce is $2.25.

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3 years ago

Which interval for the graphed function has a local minimum of 0?

koban [17]

Answer:

{2,4} I know cause I JUST took the same test yesterday :) I guess I didin't help much huh

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3 years ago

Read 2 more answers

Please help me solve what is on that document

In-s [12.5K]

The most misleading graph is graph B because the blue rectangle and the red rectangle do not have the same width when plotted on the same scale

<h3>The ratio of the median weekly earnings</h3>

From the graph, we have the median weekly earnings to be:

High school diploma = $750
Bachelor's degree = $1250

So, the ratio is:

Ratio = $750 : $1250

Simplify

Ratio = 3 : 5

Hence, the ratio of the median weekly earnings is 3 : 5

<h3>The ratio of the area of the red rectangle to the blue rectangle in graph A?</h3>

In (a), we have:

Ratio = 3 : 5

The scale on the horizontal axis is given as:

1 unit per grid mark

Both rectangles have a width of 1 unit.

So, we have:

Ratio = 3 * 1: 5 * 1

Simplify

Ratio = 3 : 5

Hence, the ratio of the area of the red rectangle to the blue rectangle in graph A is 3 : 5

<h3>The ratio of the area of the red rectangle to the blue rectangle in graph B?</h3>

In (a), we have:

Ratio = 3 : 5

The scale on the horizontal axis is given as:

1 unit per grid mark

The red rectangle has a width of 3 units, while the blue has 5 units as its width

So, we have:

Ratio = 3 * 3 : 5 * 5

Simplify

Ratio = 9 : 25

Hence, the ratio of the area of the red rectangle to the blue rectangle in graph B is 9 : 25

<h3>The ratio of the volume of the red cube to the blue cube in graph C?</h3>

In (a), we have:

Ratio = 3 : 5

The scale on the horizontal axis is given as:

1 unit per grid mark

The red rectangle has a width of 3 units, while the blue has 5 units as its width.

Since the base are squares, we have:

Ratio = 3 * 3 * 3 : 5 * 5 * 5

Simplify

Ratio = 27 : 125

Hence, the ratio of the volume of the red cube to the blue cube in graph C is 27 : 125

<h3>The most misleading graph</h3>

The most misleading graph is graph B.

This is so because the blue rectangle and the red rectangle do not have the same width when plotted on the same scale

Read more about bar charts at:

brainly.com/question/24741444

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7 0

2 years ago

An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the

DedPeter [7]

<em><u>The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:</u></em>

$d = -16t^2 + 1000$

<em><u>Solution:</u></em>

<em><u>The object falls, its distance, d, above the ground after t seconds, is given by the formula:</u></em>

$d = -16t^2 + 1000$

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

$-16t^2 + 1000 > 300$

Solve the inequality

Subtract 1000 from both sides

$-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700$

$16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < \frac{700}{16}\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{\frac{700}{16}}\\\\t < \pm 6.61$

Time cannot be negative

Therefore,

t < 6.61

And the inequality used is: $-16t^2 + 1000>300$

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3 years ago