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bonufazy [111]
3 years ago
9

Kyle sells used cars he is paid $14/hour plus an 8% commission on sales what dollar amount of car Sales must kyle to earn $1200

in 38-h work week
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
5 0
The answer is $8,350 in car sales.  By working 38 hours at $14/hour, Kyle will $532 from wages alone.  Subtracting those wages from the total amount to be earned of $1,200 leaves $668, which is the amount Kyle has to earn in commissions.  Dividing $668 by 8% gets you to the $8,350.
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Write a polynomial function, p(x) with degree 3 that has p(7)=0
MArishka [77]

Answer:

p (x) = x^{3} - 21x^{2}+ 147x - 343

is the required polynomial with degree 3 and p ( 7 ) = 0

Step-by-step explanation:

Given:

p ( 7 ) = 0

To Find:

p ( x ) = ?

Solution:

Given p ( 7 ) = 0 that means substituting 7 in the polynomial function will get the value of the polynomial as 0.

Therefore zero's of the polynomial is seven i.e 7

Degree : Highest raise to power in the polynomial is the degree of the polynomial

We have the identity,

(a -b)^{3} = a^{3}-3a^{2}b +3ab^{2} - b^{3}

Take a = x

        b = 7

Substitute in the identity we get

(x -7)^{3} = x^{3}-3x^{2}(7) +3x(7)^{2} - 7^{3}\\(x -7)^{3} = x^{3}-21x^{2} +147x - 343

Which is the required Polynomial function in degree 3 and if we substitute 7 in the polynomial function will get the value of the polynomial function zero.

p ( 7 ) = 7³ - 21×7² + 147×7 - 7³

p ( 7 ) = 0

p (x) = x^{3} - 21x^{2}+ 147x - 343

4 0
3 years ago
Roasted peanuts cost 3 per pound at the local market. What is the cost of a 6 pound bag of peanuts
Novosadov [1.4K]
6 x 3  you do the math
4 0
3 years ago
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A grocer pays $7.00 for each carton of 14 cantaloupes. Which inequality describes p, the set of prices, in dollars, that he can
Deffense [45]
I can tell you that is 50 cents for cantaloupe at that price....
So I think he'd have to charge $1.50. He'd get what he paid for back plus a dollar.   If C= one cantaloupe ....it would look something like
 p > $1.50c   
 BECAUSE 1.50 x 14 = 21 minus the 7 he paid would leave you with 14... on dollar per cantaloupe... so the price can be anything greater than $1.50
4 0
3 years ago
Read 2 more answers
A 90° angle is divided into 2 angles.
Lemur [1.5K]

Answer:

this angle's sum is 90°

(3x+40)°+(4x-6)=90°

7x+34=90°

7x=90-34

7x=56

x=56/7

x=8

3x+40 = 3×8+40 = 64°

4x-6 = 4×8-6 = 26°

8 0
3 years ago
Problem 10: A tank initially contains a solution of 10 pounds of salt in 60 gallons of water. Water with 1/2 pound of salt per g
AysviL [449]

Answer:

The quantity of salt at time t is m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} }), where t is measured in minutes.

Step-by-step explanation:

The law of mass conservation for control volume indicates that:

\dot m_{in} - \dot m_{out} = \left(\frac{dm}{dt} \right)_{CV}

Where mass flow is the product of salt concentration and water volume flow.

The model of the tank according to the statement is:

(0.5\,\frac{pd}{gal} )\cdot \left(6\,\frac{gal}{min} \right) - c\cdot \left(6\,\frac{gal}{min} \right) = V\cdot \frac{dc}{dt}

Where:

c - The salt concentration in the tank, as well at the exit of the tank, measured in \frac{pd}{gal}.

\frac{dc}{dt} - Concentration rate of change in the tank, measured in \frac{pd}{min}.

V - Volume of the tank, measured in gallons.

The following first-order linear non-homogeneous differential equation is found:

V \cdot \frac{dc}{dt} + 6\cdot c = 3

60\cdot \frac{dc}{dt}  + 6\cdot c = 3

\frac{dc}{dt} + \frac{1}{10}\cdot c = 3

This equation is solved as follows:

e^{\frac{t}{10} }\cdot \left(\frac{dc}{dt} +\frac{1}{10} \cdot c \right) = 3 \cdot e^{\frac{t}{10} }

\frac{d}{dt}\left(e^{\frac{t}{10}}\cdot c\right) = 3\cdot e^{\frac{t}{10} }

e^{\frac{t}{10} }\cdot c = 3 \cdot \int {e^{\frac{t}{10} }} \, dt

e^{\frac{t}{10} }\cdot c = 30\cdot e^{\frac{t}{10} } + C

c = 30 + C\cdot e^{-\frac{t}{10} }

The initial concentration in the tank is:

c_{o} = \frac{10\,pd}{60\,gal}

c_{o} = 0.167\,\frac{pd}{gal}

Now, the integration constant is:

0.167 = 30 + C

C = -29.833

The solution of the differential equation is:

c(t) = 30 - 29.833\cdot e^{-\frac{t}{10} }

Now, the quantity of salt at time t is:

m_{salt} = V_{tank}\cdot c(t)

m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })

Where t is measured in minutes.

7 0
3 years ago
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