Kyle sells used cars he is paid $14/hour plus an 8% commission on sales what dollar amount of car Sales must kyle to earn $1200
1 answer:
You might be interested in
Answer:
The lines are parallel, with the same slope of 5.
Step-by-step explanation:
Remember that if slopes are the same, then the lines are parallel. If the slopes are opposite reciprocals, they are perpendicular. If they are neither of those cases, then they would be neither.
1) Since y = 5x + 1 is already in slope-intercept format (y = mx + b, in which m represents the slope) we know that 5 is the slope of that equation.
2) To find the slope of -5x + y = 6, let's just convert it to the slope-intercept format by isolating y on the left side like so:
(All you need to do is move -5x to the right side of the equation.) So, by looking at y = 5x + 6, we can do the same thing we did from step 1 and find that the slope is 5.
3) Since both of the equations' slopes are 5, they share the same slope - therefore, they are parallel.
Hope this helps! Please do not hesitate to ask any questions.
Answer:
The required function is:
The price for each feeder to maximize profit should be $13.
The maximum weekly profit is $147
Step-by-step explanation:
Consider the provided information.
Part (A)
The materials for each feeder cost $6, and the society sells an average of 30 per week at a price of $10 each.
Let x be the price per feeder.
Profit = Revenue - cost
So the profit per feeder is
If we increase then for every dollar increase, it loses 3 sales per week.
This can be written as:
Where x-10 represents the increase in price and 3 represents the decrease in sales per week.
Thus the profit will be:
Hence, the required function is:
Part (B) What price should the society charge for each feeder to maximize profits? What is the maximum weekly profit?
The above function is a downward parabola so the maximum will occur at vertex.
The x coordinate of the vertex of parabola is:
Substitute a=-3, b=78 and c=-360 in above.
Hence, the price for each feeder to maximize profit should be $13.
Now substitute the value of x in
Hence, the maximum weekly profit is $147