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viva [34]
3 years ago
7

***Function table***

Mathematics
1 answer:
Afina-wow [57]3 years ago
8 0

Answer:

y for each x value

-18

52

-13

-8

32

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I NEED HELP I WILL MARK IT BRAINLY
lana66690 [7]

Answer:

W=2/(P-2L)

Step-by-step explanation:

4 0
4 years ago
Find the distance traveled by a particle with position (x, y) as t varies in the given time interval. x = 5 sin2 t, y = 5 cos2 t
rodikova [14]
\begin{cases}x(t)=5\sin2t\\y(t)=5\cos2t\end{cases}\implies\begin{cases}\frac{\mathrm dx}{\mathrm dt}=10\cos2t\\\frac{\mathrm dy}{\mathrm dt}=-10\sin2t\end{cases}

The distance traveled by the particle is given by the definite integral

\displaystyle\int_C\mathrm dS=\int_0^{3\pi}\sqrt{\left(\frac{\mathrm dx}{\mathrm dt}\right)^2+\left(\frac{\mathrm dy}{\mathrm dt}\right)^2}\,\mathrm dt

where C is the path of the particle. The distance is then

\displaystyle\int_0^{3\pi}\sqrt{100\cos^22t+100\sin^22t}\,\mathrm dt=10\int_0^{3\pi}\mathrm dt=30\pi
6 0
3 years ago
Find the third side in simplest radical form:<br> 25
Gre4nikov [31]

Answer:

<h3>\boxed{  \bold{24}}</h3>

Step-by-step explanation:

\mathsf{given}

\mathsf{hypotenuse(h) = 25}

\sf{perpendicular (p) = 7}

\sf{base(b) = }?

Now, Using Pythagoras theorem

\sf{{h}^{2}  =  {p}^{2}  +  {b}^{2} }

plug the values

⇒\sf{  {25}^{2}  =  {7}^{2}  +  {b}^{2} }

Evaluate the power

⇒\sf{625 = 49 +  {b}^{2} }

Swap the sides of the equation

⇒\sf{49 +  {b}^{2}  = 625}

Move constant to right hand side and change it's sign

⇒\sf{ {b}^{2}  = 625 - 49}

Calculate the difference

⇒\sf{ {b}^{2}  = 576}

Squaring on both sides

⇒\sf{b = 24}

Hope I helped!

Best regards!

8 0
3 years ago
Identify the class width for the given frequency distribution
Fittoniya [83]

Answer: not enough information

Step-by-step explanation:

6 0
3 years ago
Please answer this question now
vichka [17]

Answer:

320 sq in

Step-by-step explanation:

4(1/2*8*16) + (8*8)

= 4(64) + (64)

= 5(64)

= 320

6 0
3 years ago
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