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Alisiya [41]
3 years ago
9

Use the domain {-1, 0, 1, 2, 3, 4} and plot the points on the graph that would best satisfy the equation y = 2x.

Mathematics
1 answer:
Dmitrij [34]3 years ago
4 0
Domain is ur x values

y = 2x...when x = -1
y = 2(-1)
y = -2.....(-1,2) satisfies this equation

y = 2x....when x = 0
y = 2(0)
y = 0....(0,0) satisfies it

y = 2x....when x = 1
y = 2(1)
y = 2....so (1,2) satisfies it

y = 2x....when x = 2
y = 2(2)
y = 4....(2,4) satisfies it

y = 2x...when x = 3
y = 2(3)
y = 6.....(3,6) satisfies it

y = 2x...when x = 4
y = 2(4)
y = 8.....(4,8) satisfies it
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Compare the properties of each function. Please help I will give brainliest.
prisoha [69]

9514 1404 393

Answer:

  • both are linear functions with a y-intercept of 3 and domain of all real numbers
  • f(x) has positive slope, so a range of all real numbers
  • g(x) has zero slope, so a range of only the value 3

Step-by-step explanation:

Both functions are shown in the attached graph. Both are linear functions with a y-intercept of 3. Both have a domain of all real numbers.

Function A has a positive slope, so has a range of all real numbers.

Function B has a zero slope, so its range is the single number y = 3.

5 0
3 years ago
Please help with this question.
Aneli [31]

Answer:

if I have my calculations right it would be £120

6 0
3 years ago
3) What is 4.01 X 10° written in standard form<br> A. 0.401<br> B. 4.001<br> C. 4.01<br> D. 40.1
Leya [2.2K]
The Answer is-
D
Explanation-
The Place Of the 0 In 10 Is 1, So we move 1 digit
To that side.
7 0
3 years ago
Read 2 more answers
If P(x) = ax 3 + bx - 3 and P(-1)-0, then the value of P(1) is:
sergey [27]

Answer:

(a) -6

Step-by-step explanation:

P(x) = ax^3 +bx - 3

  • P(-1) = -a-b-3 = 0
  • therefore a+b=-3
  • P(1) = a+b-3
  • P(1) = -3 - 3 = -6
  • (a)
7 0
3 years ago
An engineer is planning a new water pipe installation. The circular pipe has a diameter of d=20\text{ cm}d=20 cmd, equals, 20, s
aivan3 [116]

Answer: The answer is 314.28 cm² (approx.).


Step-by-step explanation:  Given that an engineer is going to install a new water pipe. The diameter of this circular pipe is, d = 20 cm.

We need to find the area 'A' of the circular cross-section of the pipe.

Given, diameter of the circular section is

\textup{d}=20~\textup{cm}.

So, the radius of the circular cross-section will be

\textup{r}=\dfrac{\textup{d}}{2}=\dfrac{20}{2}=10~\textup{cm}.

Therefore, cross-sectional area of the pipe is

\textup{A}=\pi \textup{r}^2=\dfrac{22}{7}(10)^2=\dfrac{2200}{7}=314\dfrac{2}{7}=314.28~.~.~.~\textup{cm}^2.

Thus, the answer is 314.28 cm² (approx.).

4 0
4 years ago
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