Given a term in an arithmetic sequence and the common difference, find the first five terms
1 answer:
Step-by-step explanation:
we come with a1
a(n) = a1 +(n-1)d
a(35) = a1 +(35-1)-10=-312
So a1=-312+340= 28
first five terms:
a1= 28
a(2) = 28 +(2-1)-10=18
a(3) = 28 +(3-1)-10=8
a(4) = 28 +(4-1)-10=-2
a(5) = 28 +(5-1)-10=-12
hope it helps
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1,129.872 to the nearest hundred is 1,100
Sorry I don’t understand 1-100=99 sorry
Answer:
C. (f – g)(x) = –2x – 2
Step-by-step explanation:
(f – g)(x) = f(x) – g(x)
= (–5x – 4) – (–3x – 2)
= –2x – 2
42 is the answers I the problem
