Question

Given a term in an arithmetic sequence and the common difference, find the first five terms

Answer 1

Step-by-step explanation:

we come with a1

a(n) = a1 +(n-1)d

a(35) = a1 +(35-1)-10=-312

So a1=-312+340= 28

first five terms:

a1= 28

a(2) = 28 +(2-1)-10=18

a(3) = 28 +(3-1)-10=8

a(4) = 28 +(4-1)-10=-2

a(5) = 28 +(5-1)-10=-12

hope it helps