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aniked [119]
3 years ago
8

(sina + cosa +1)/(sina+cosa-1)- (1+sina-cosa)/(1-sina+cosa)=2(1+coseca)​

Mathematics
1 answer:
denis23 [38]3 years ago
3 0

I solve this question with further steps which was not so much necessary, but it's correct

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Which values of a, b, and c represent the answer in simplest form 9/11 divided by 5/11
Elenna [48]

Answer:

1 4/5

Step-by-step explanation:

8 0
3 years ago
A jewlery supply shop buys silver chains from a manufacturer for c dollars each, and then sells the chains at a 57% markup
kirza4 [7]

11. 57% = 0.57

12.  retail price = c + (0.57c)

13.  retail price = 45 + (0.57 x 45)

retail price = 45 + 25.65

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14. 57% was added to the original price of the chain which is $25.65

4 0
3 years ago
Evaluate 7w-14 for w=9.
sashaice [31]
That's the answer and how you do it.

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5 0
4 years ago
Solve the following: 3.12 × 1,000 = _____.
torisob [31]

Answer:

60000000.00

Step-by-step explanation:

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8 0
3 years ago
The circle graph shows the percentage of time Jacob spent on homework in each subject last week.Time Spent on Homework12.5%25%ar
Goshia [24]

We are given a circle graph that shows the time spent on homework last week.

Jacob spent a total of 16 hours doing homework.

The time spent on doing science homework is given by

\begin{gathered} t_{\text{science}}=25\%\: of\: 16 \\ t_{\text{science}}=\frac{25}{100}\: \times\: 16=4\: \text{hours} \end{gathered}

The time spent on doing band practice is given by

\begin{gathered} t_{\text{band}}=12.5\%\: of\: 16 \\ t_{\text{science}}=\frac{12.5}{100}\: \times\: 16=2\: \text{hours} \end{gathered}

The difference between the time spent on science homework and band practice is

difference=t_{\text{science}}-t_{\text{band}}=4-2=2\: \text{hours}

Therefore, Jacob spent 2 more hours on science homework than band practice.

4 0
1 year ago
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