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2 years ago

Salvador reads 13 books from the library each month for y months in a row. Write an expression to

Mathematics

2 answers:

Dahasolnce [82]2 years ago

8 0

Answer:

a lot

Step-by-step explanation:

MaRussiya [10]2 years ago

8 0

13*5=x
x would equal 65
So 13*5=65
Salvador read 65 books in five months.

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Sveta_85 [38]

Answer:

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2 years ago

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9 stores is 3% of how many stores?

hichkok12 [17]

Hello there! We can solve this question by writing and solving a proportion. Set it up like this:

9/x = 3/100.

This is because 9 is 3% of x number of stores and percents are parts of 100. Setting it up like this will help us get the correct answer. Cross multiply the values . 9 * 100 is 900 and 3 * x = 3x. You get 900 = 3x. Now, divide each side by 3 to isolate the x. 3x/3 cancels out the x. 900/3 is 300. There. x = 300. 9 stores is 3% of 300 stores.

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3 years ago

Read 2 more answers

Stuck on this question because I left my calculator and the others aren’t working please help

Pavlova-9 [17]

Answer:

-94%, -0.925, -9/10, -8/9

Step-by-step explanation:

-94% = -0.94

-8/9 = -0.89

-9/10 = -0.90

Since the values are negative the order is opposite then if they were all positive.

8 0

2 years ago

If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(

timama [110]

Use the change-of-basis identity,

$\log_x(y) = \dfrac{\ln(y)}{\ln(x)}$

to write

$xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}$

Use the product-to-sum identity,

$\log_x(yz) = \log_x(y) + \log_x(z)$

to write

$xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}$

Redistribute the factors on the left side as

$xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}$

and simplify to

$xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)$

Now expand the right side:

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}$

Simplify and rewrite using the logarithm properties mentioned earlier.

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1$